Question

(x +8/3)2 +y2=1 what is it's center(. ,. ) what is it's radius​

Answer 1

Answer: Center is $(-\frac{8}{3}, 0)$ and radius is 1.

Step-by-step explanation: The center of a circle $(x-a)^{2} + (y-b)^{2} = r^{2}$ is (a,b) & the radius is r. a=$--\frac{8}{3} = \frac{8}{3}$ , b=0, and r=$\sqrt{1}$=1