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zaharov [31]
3 years ago
5

The Five Fives Challenge

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
Well I think since tim Allen is cool your correct
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Pls help <3 i mean i’m sure it’s easy but i don’t know what to write.
I am Lyosha [343]
Circumference/Diameter = pi = 3.14
C/D = pi = 3.14
5 0
3 years ago
PLEEEEEEEASE HELLLP What is the midpoint of segment RT with endpoints at (-5,2) and (1, -3)?
Grace [21]

Answer:

-2, -1/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me and explain
yan [13]

TOTAL IS $10


If the party costs $5 and each additional person is $1 and she invites 5 more 5 X 1 = 5


OR 1 + 1 + 1 + 1 + 1

4 0
3 years ago
What if you magnified the image of a cluster fly by 9 times 10 to the third power?
densk [106]

It would either be 9*(10^3) which would be <em>9000</em>.

Or, it would be (9*10)^3, which equals <em>729000</em>.

Please try and get another answer to make sure!

6 0
3 years ago
Rhombus EFGH is shown. What is the measure of ∠HGJ?
MaRussiya [10]

Answer:

∠HGJ = 35°

Step-by-step explanation:

Although the question is somewhat incomplete, I have tried to reconstruct the question as much as possible to aid understanding (attached is the pictorial representation of the rhombus).

Firstly, it is important to note that rhombuses are parallelograms which have all sides equal and whose diagonals are perpendicular to each other. In addition to this, their diagonals bisect one other.

Mathematically, |EF| = |FG| = |GH| = |HE|

Another property which rhombuses have is that their opposite angles are equal.

Mathematically, ∠E = ∠G, ∠H = ∠F

The adjacent angles in a rhombus are supplementary. This means that the sum of angles closest to each other is 180°.

Mathematically, ∠E + ∠F = 180°, ∠F + ∠G = 180°, ∠G + ∠H = 180°,

∠H + ∠E = 180°

The question gave us ∠GHE and asked us to find ∠HGJ (denoted as θ in the picture attached). Note that ∠GHE means ∠H. That is, ∠GHE ⇒ ∠H

∠GHE or ∠H = 110°

From the properties of rhombuses (earlier stated), we know that adjacent angles in a rhombus are supplementary

Mathematically,

∠GHE + ∠FGH ⇒ 110° + ∠FGH = 180° ⇒ ∠FGH = 180° - 110°

∠FGH or ∠G = 70°

To calculate for ∠HGJ, we divide ∠FGH by 2, we have:

∠HGJ = ∠FGH ÷ 2 = 70° ÷ 2

∠HGJ = 35°

3 0
3 years ago
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