The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.
Let the required length be x, then

Therefore, the height of the airplane above the tower is 1,819.85 feet.
Answer:
1) a. Move farther into the tails
2) a. Decreases
Step-by-step explanation:
Hello!
1)
Let's say for example that you are making a confidence interval for the mean, using the Z-distribution:
X[bar] ±
* 
Leaving all other terms constant, this are the Z-values for three different confidence levels:
90% 
95% 
99% 
Semiamplitude of the interval is
d=
* 
Then if you increase the confidence level, the value of Z increases and so does the semiamplitude and amplitude of the interval:
↑d= ↑
* 
They have a direct relationship.
So if you change α: 0.05 to α: 0.01, then the confidence level 1-α increases from 0.95 to 0.99, and the boundaries move farther into the tails.
2)
The significance level of a hypothesis test is the probability of committing a Type I error.
If you decrease the level from 5% to 1%, then logically, the probability decreases.
I hope this helps!
Answer:
i really dont know
Step-by-step explanation:
(2/7)^2 x (7/9)^2
((2^2)/(7^2)) x ((7^2)/(9^2))
(4/49) x (49/81)
*Cross multiply*
(4/81)