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Mama L [17]
3 years ago
15

Suppose that twelve bats was used in the experiment. For each trail, the zoo keeper pointed to one of two "feeders". Suppose tha

t the bats went to the correct feeder (the one that the zoo keeper pointed at) 9 times. Find the 95% confidence interval for the population proportion of times that the bats would follow the point.
Mathematics
1 answer:
marshall27 [118]3 years ago
5 0

Answer:

The 95% confidence interval for the population proportion of times that the bats would follow the point is (0.505, 0.995).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

There are 12 bats, and 9 would follow the feeder. This means that n = 12 and \pi = \frac{9}{12} = 0.75.

Find the 95% confidence interval for the population proportion of times that the bats would follow the point.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.96\sqrt{\frac{0.75*0.25}{12}} = 0.505

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.96\sqrt{\frac{0.75*0.25}{12}} = 0.995

The 95% confidence interval for the population proportion of times that the bats would follow the point is (0.505, 0.995).

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3 years ago
1. Which ordered pairs are solutions to the inequality –3x + y ≥ 7?
Murrr4er [49]
Q1. The answers are (–1, 8), (0, 7), (3, 18)

<span>–3x + y ≥ 7
</span>Let's go through all choices:

<span>(–2, –3) 
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6 - 3 ≥ 7
3 ≥ 7       INCORRECT

(–1, 8) 
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3 + 8 ≥ 7
11 ≥ 7       CORRECT

(0, 7) 
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0 + 7 ≥ 7
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(1, 9) 
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Q2. The answers are:
5x + 12y ≤ 80
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<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes

</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
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Jude needs at least 4 small boxes on the shelf: x ≥ 4

Let's check if y can be 0:
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5x + 0 ≤ 80
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x ≥ 4 can include x ≤ 16

So, y can be 0: y ≥ 0
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2 years ago
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ArbitrLikvidat [17]

Answer:

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Angle 3: 15

Step-by-step explanation:

Angle 1: x

Angle 2: 2x

Angle 3: x-40

The total degrees for all the angles in a triangle add up to 180, so we now have the equation x+2x+x-40=180. From here we solve to get 55 degrees for x, so angle 1 is 40 degrees, angle 2 is 110 (2 times 40) and the third angle is 15 (55-40).  

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