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3 years ago

. Simplify by using the Distributive Property 4(4f-2g)

Mathematics

2 answers:

Vesna [10]3 years ago

7 0

Answer:

16f - 8g

Step-by-step explanation:

You would multiply the terms in the middle by 4 so 4f*4 would be 16f since 4*4 is 16 and then 4*2g would be 8g since 4*2 is 8

Bad White [126]3 years ago

6 0

Answer:

the answer is 16f-8g

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2. Determine the value of x. Assume the segments that appear tangent

dimulka [17.4K]

Answer:

x = 16.8

Step-by-step explanation:

To get the value of x, we use Pythagoras’ theorem since what we have is a right angled triangle

Mathematically, we have it that;

the square of the hypotenuse (21) equals the sum of the squares of the two other sides

21^2 = 12.6^2 + x^2

x^2 = 21^2 - 12.6^2

x^2 = 282.24

x = √282.24)

x = 16.8

6 0

3 years ago

Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

a. The system of equations that models the situation is....

$0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40$

b. The solution to the system: x = 2 and y = 4

The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0

3 years ago

How many terms are in the arithmetic sequence 1313, 1616, 1919, ……, 7070, 7373?

Ede4ka [16]

The formula in getting the arithmetic sequence:
an = a1 + (n – 1)d.

We can substitute the values in order for us to know how many terms the sequence has.

an = 7373
a1 = 1313
d = 303

an = a1 + (n – 1)d
7373 = 1313 + (n-1) 303
7373 = 1313 + 303n - 303
-303n = 1313 - 303 - 7373
303n = -1313 + 303 + 7373
303n = 6363
n = 21

So, there are 21 terms in the sequence given.

3 0

3 years ago

Riley has collected surveys for her final thesis project. One one question, 46.1% of respondents said that conditions were impro

ira [324]

Answer:

The maximum value of the confidence interval for this set of survey results is 51.73%.

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds depend on the sample proportion and on the margin of error.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this question:

Sample proportion: 46.1%

Margin of error: 5.63%.

Maximum value is the upper bound:

46.1+5.63 = 51.73

The maximum value of the confidence interval for this set of survey results is 51.73%.

5 0

3 years ago

Rewrite y=a(1/3)^3t in the form y = a(1+r)^t or y = a(1 –r)^t

pshichka [43]

Answer:

sorry

Step-by-step explanation:

sorry I cannot help u because I have not seen this type of question before and I have not learn I am in 7 classes

6 0

3 years ago