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3 years ago

Can someone help me on this question

Mathematics

2 answers:

stich3 [128]3 years ago

5 0

The answer for this question is b

Sphinxa [80]3 years ago

4 0

It’s b the Answer...........

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Help,anyone can help me do quetion.

3241004551 [841]

Answer:

(a) x = $128^{o}$

(b) x = $74^{o}$

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

= 3 x 180

= $540^{o}$

Thus,

x + 90 + 76 + 110 + 136 = $540^{o}$

x + 412 = $540^{o}$

x = $540^{o}$ - 412

x = $128^{o}$

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

= $142^{o}$

y = $142^{o}$

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = $540^{o}$

z + 434 = $540^{o}$

z = $540^{o}$ - 434

= $106^{o}$

z = $106^{o}$

But, x + z = $180^{o}$

Then;

x + $106^{o}$ = $180^{o}$

x = $180^{o}$ - $106^{o}$

= $74^{o}$

x = $74^{o}$

7 0

3 years ago

What is the equation?

AfilCa [17]

Answer:

Step-by-step explanation: and explain

3 0

2 years ago

Read 2 more answers

A multiple must be greater than or equal to the largest starting number. True or False

podryga [215]

I'll use multiples of 2 and 4 as an example:

Multiples of 2: 2, 4, 6, 8...

Multiples of 4: 4, 8, 12, 16...

The least common multiple in this case is 4. The LCM is always ≥ the largest starting number, which is 4 for this example. Therefore, the statement is true.

<em>Hope this helps! :)</em>

8 0

3 years ago

What is the answer for number six?

Anna71 [15]

I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0

6 0

3 years ago

Mary must choose a new password where the first and last choices are possibly repeated lowercase letters; the second and third

Salsk061 [2.6K]

The number of ways she can choose a password is 3986236800

<h3>In how many ways can she choose a password?</h3>

The given parameters and the possible selection of characters are:

First and last choices are possibly repeated lowercase letters;

There are 26 lower characters.

Since the characters can be repeated, then we have

First = 26

Last = 26

The second and third positions must be distinct uppercase letters

There are 26 upper characters.

Since the characters are distinct, then we have

Second = 26

Third = 25

The fourth position must be a # , $, or & symbol;

So, we have

Fourth = 3

The next four positions are distinct nonzero digits.

There are 9 nonzero digits.

Since the digits are distinct, then we have

Next = 9, 8, 7, 6

The number of ways she can choose a password is

Ways = First * Second * Third * Fourth * Next * Last

So, we have

Ways = 26 * 26 * 25 * 3 * 9 * 8 * 7 * 6 * 26

Evaluate the product

Ways = 3986236800

Hence, the number of ways she can choose a password is 3986236800