Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
First, let's find the x and y intercepts
In the first equation
y - 4x = -1
Put x =0
y= - 1
(0, -1)
Put y=0 and the n solve for x
0 - 4x = -1
-4x = -1
x=0.25
(0.25 , 0)
The points for the first equation is (0, -1 ) and (0.25, 0)
Next is to find the intercts for the second equation
y + x = 4
put x=0
y = 4
(0, 4)
Put y =0
0 + x = 4
x = 4
( 4, 0)
The points for the second equation are;
(0, 4) and (4, 0)
Below is the graph
Answer:
x = 40 in
Step-by-step explanation:
the missing angle in the triangle on the left is
180° - (74 + 51)° = 180° - 125° = 55°
the missing angle in the triangle on the right is
180° - (74 + 55)° = 180° - 129° = 51°
the 2 triangles have 3 pairs of congruent angles and are therefore congruent.
Corresponding sides and angles are then congruent
consider the corresponding sides opposite 74° , that is x and 40 in , so
x = 40 in
Answer:Thanks
Step-by-step explanation:
Answer:
19% done
81% left
Step-by-step explanation:
95/500=19
100-19=81