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2 years ago

What is the difference of 23x and 9x?

2 answers:

5 0

The problem wants to calculate the said problem and choose among the following choices that could be the difference of the 23x and 9x. Base on my further computation and systematically figuring it out, my answer would be C.14x. I hope you are satisfied with my answer and feel free to ask for more

BaLLatris [955]2 years ago

4 0

Subtract 9x from 23x yields 14x. This was done by subtracting algebraically the variables.

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Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele

garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

$h = -4.9(t - 13)(t + 2).$

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

$h = -4.9(t - 13)(t + 2).$ becomes

$0 = -4.9(t - 13)(t + 2).$

Divide through by -4.9

$0 = (t - 13)(t + 2).$

Reorder the expression

$(t - 13)(t + 2) = 0.$

Split

$t-13 = 0$ or $t + 2 = 0$

This gives:

$t = 13$ or $t = -2$

But time can't be negative, So:

$t = 13$

6 0

2 years ago

[Will award brainliest if correct!] It takes a painter and his friend 8 hours to paint a room. if the painter was working alone,

Keith_Richards [23]

Answer:

it would take him 10 hours

5 0

2 years ago

EASY 10 PTS

ollegr [7]

The solution is: 252. 14x18

7 0

2 years ago

Working together, it takes Sam, Jenna, and Francisco two hours to paint one room. When Sam works alone, he can paint one room in

lutik1710 [3]

Answer: 12 hours

Step-by-step explanation:

Given : Working together, it takes Sam, Jenna, and Francisco two hours to paint one room.

When Sam works alone, he can paint one room in 6 hours. When Jenna works alone, she can paint one room in 4 hours.

Let 't' be the time taken by Francisco to paint one room on his own.

Then , we have

Rate of work of Sam +Rate of work of Jenna + Rate of work of Francisco =Rate of work they all do together

$\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{t}=\dfrac{1}{2}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{1}{6}+\dfrac{1}{4})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{4+6}{24})$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{10}{24}$

i.e. $\dfrac{1}{t}=\dfrac{1}{2}-\dfrac{5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{6-5}{12}$

i.e. $\dfrac{1}{t}=\dfrac{1}{12}$

i.e. t= 12

Hence, Francisco would take 12 hours to paint one room on his own.

8 0

3 years ago

Jeffrey went to the movies with his friends. The tickets cost $8.50 each for students and they spent $15.00 altogether at the co

LenaWriter [7]

Answer:

4 people

Step-by-step explanation:

Let's first write an equation.

We want to find the number of tickets t

The total was $49 so our equation will equal $49 and they spent $15 in snacks so on the other side of the eqaution we have to add $15, on the same side as the snacks we need to add in the cost of tickets, which is $8.50 multiplies by t, or the total number of tickets.

$49 = $8.50t + $15

Solve for t, first subtract $15 from both sides.

$49 - $15 = $8.50t

$34 = $8.50t Divide both sides by $8.50

$34/$8.50 = $8.50t/$8.50

$34/$8.50 = t

4 = t

4 tickets meaning 4 people went.

7 0

2 years ago