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Nostrana [21]
3 years ago
8

Evaluate each of the integrals (here δ(t) is the dirac delta function) (1) ∫∞−∞e5tδ(t−2)dt= (2) ∫∞−∞cos(2t)δ(t−5)dt= (3) ∫∞0e−st

cos(3t)δ(t−2)dt= (4) ∫∞0e−stt3sin(t)δ(t−3)dt\)=
Mathematics
1 answer:
Viktor [21]3 years ago
8 0
\delta(x) has the property that for any continuous f with support in \mathbb R,

\displaystyle\int_{-\infty}^\infty f(x)\delta(x-c)\,\mathrm dx=f(c)

where c\in\mathbb R. So we have

\displaystyle\int_{-\infty}^\infty e^{5t}\delta(t-2)\,\mathrm dt=e^{10}

\displaystyle\int_{-\infty}^\infty\cos2t\,\delta(t-5)\,\mathrm dt=\cos10

The remaining two integrals are identical to the Laplace transforms of \cos3t\,\delta(t-2) and t^3\sin t\,\delta(t-3). For these, we have the property that

\mathcal L_s\{f(t)\delta(t-c)\}=f(c)e^{-sc}

so we get

\displaystyle\int_0^\infty e^{-st}\cos3t\,\delta(t-2)\,\mathrm dt=\mathcal L_s\{\cos3t\,\delta(t-2)\}=\cos6\,e^{-2s}

\displaystyle\int_0^\infty e^{-st}t^3\sin t\,\delta(t-3)\,\mathrm dt=\mathcal L_s\{t^3\sin t\,\delta(t-3)\}=27\sin3\,e^{-3s}
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