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Gwar [14]
3 years ago
5

Help Im still stuck i hate geometry

Mathematics
1 answer:
natta225 [31]3 years ago
3 0

<ABD + <DBC = 95

2x + 23 + 9x - 5 = 95

11x + 18 = 95

11x = 77

 x = 7

<ABD = 2(7) + 23 = 14 + 23 = 37

<DBC = 9x - 5 = 9(7) - 5 = 63 - 5 = 58

Answer

<ABD = 37°

<DBC = 58°

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p(the person does not use any facility)= 59/130

6 0
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Mali bought a new car. She drove 63 miles the first month and 64 miles the second month. How much further did she drive the seco
Anvisha [2.4K]

Answer:

64-63=1 so she drove 1 extra miles the second month

Step-by-step explanation:

4 0
3 years ago
I have 47 nickels and dimes worth $4.20. How many of each type of coin do I have?
soldi70 [24.7K]

Answer:

37 dimes and 10 nickels

Step-by-step explanation:

let d = # dimes

let n = # nickels

we can set up a system of equations:

n + d = 47

.05n + .10d = 4.2

if we solve the first equation for 'n' we get:  

n = 47-d

now we can substitute this in for 'n' in the second equation:

.05(47-d) + .10d = 4.2

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subtract 2.35 from each side to get:

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d = 1.85÷.05

d = 37

if d+n = 47 and d=37 then n = 10

Check:

.05(10) + .1(37) should equal 4.2

.50 + 3.7 = 4.2  [It Checks Out]

6 0
2 years ago
Find all solutions in the integers of the equation ||x−3|−5| = 10, where the bars indicate absolute value.
Helga [31]

Answer:

x = 18 or x = -12.

Step-by-step explanation:

||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12.  We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.

3 0
3 years ago
Midpoint.<br> (3,3), (-1,1)
Scilla [17]

Answer:

1,2

Step-by-step explanation:

3+-1=2

2/2=1  

3+1=4

4/2=2

7 0
3 years ago
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