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s344n2d4d5 [400]
3 years ago
7

How many 1/5 are in 3

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

Your answer is 15

Have a great day!

Step-by-step explanation:

You might be interested in
Solve the equation 3x-1=x+9
Sever21 [200]
5.

3x - 1 = x + 9

Subtract x on both sides

2x - 1 = 9

Add one on both sides.

2x = 10

Divide by 2 to get the x.

x = 5

Hope this helps!
5 0
3 years ago
Read 2 more answers
I need help with the problem​
maxonik [38]

Answer:

Negative line

Step-by-step explanation:

Going up is positive (think in going uphill)

Going down is negative

6 0
2 years ago
Maria bought seven boxes. A week later half of all her boxes were destroyed in a fire. There are now only 22 boxes left. With ho
Licemer1 [7]
Maria started with 37 boxes 
3 0
3 years ago
How many ways can a President and a Vice President (2 positions) be selected from a group of 10 people?
Anna35 [415]

Answer:

90

Step-by-step explanation:

There are 10 people who can be picked for the first position, which leaves 9 people who can be picked for the second position.

10 × 9 = 90

You can also use permutations.

₁₀P₂ = 90

7 0
2 years ago
Question 1- Whats the derivative of: A) f(x)= 4 cos(x) + ln(x+1)<br> B) f(x)= sec(x) X tg(x)
Kryger [21]

The derivatives for this problem are given as follows:

a) f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

b) f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

<h3>What is the derivative of the sum?</h3>

The derivative of the <u>sum is the sum of the derivatives</u>.

In this problem, the function is:

f(x) = 4\cos{x} + \ln{(x + 1)}

Using a derivative table for the derivatives of the cosine and the ln, the derivative of the function is:

f^{\prime}(x) = (4\cos{x})^{\prime} + (\ln{(x + 1)})^{\prime}

f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

What is the product rule?

The derivative of the product is given as follows:

(f(x) \times g(x))^{\prime} = f^{\prime}(x)g(x) + g^{\prime}(x)f(x)

In this problem, we have that:

  • f(x) = \sec{x}, f^{\prime}(x) = \sec{x}\tan{x}.
  • g(x) = \tan{x}, f^{\prime}(x) = \sec^2{x}.

Hence the derivative is:

f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

More can be learned about derivatives at brainly.com/question/2256078

#SPJ1

4 0
2 years ago
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