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2 years ago

What is 3 divided by 4/5

Mathematics

2 answers:

Molodets [167]2 years ago

6 0

Flip the sign so it would be 3 times 5/4 which is 15/4 which is 3.75

Veseljchak [2.6K]2 years ago

3 0

The answer is 3.75 or 3 3/4

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6(y + 8) = I need help please :)

Allushta [10]

Answer:

6y + 48

Step-by-step explanation:

Use distributive property 6 x y = 6y

(keep the plus sign btw)

6 x 8 = 48

then place it in order: 6y + 48 is your algebra expression

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2 years ago

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If the cost of 6 sandwiches and 4 drinks is $53 how much is one drink

natita [175]

Answer: The cost of one drink is $5.30.

Explanation: 6 + 4 = 10, and 53/10 = 5.3, therefore the cost of one drink is $5.30.

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Multiplicative inverse of 21/49

Komok [63]

Answer:

49/21

Step-by-step explanation:

You just have to switch the numerator and denominator so you can cancel out the number from one side of the equation in a normal problem

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3 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

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3 years ago

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Help Quickly ASAP! look at the screenshot I gave you<br><br> POINT:20

igomit [66]

Answer:

41 i think

Step-by-step explanation:

sry if its wrong and have a wonderful day :) :) :)

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2 years ago