Answer:
The cat should receive 1/5 of the can of food at each meal.
Step-by-step explanation:
Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:
1 / (450/90) = X
1/5 = X
Thus, the cat should receive 1/5 of the can of food at each meal.
Answer:
I think it b
Step-by-step explanation:
THANK YOU
Answer:
If you are a freshman, then you are required to attend orientation
Step-by-step explanation:
The if part is the given part
The then part is what is going to happen
If you are a freshman, then you are required to attend orientation
Answer: Answer Number 1; Line AB is similar to
line EF
Line BC is similar to line FG
Line CD is similar to line GH
Line DA is similar to line HE
Step-by-step explanation: First and foremost both
quadrilaterals are similar but of varying dimensions.
If we label both trapezoids as ABCD and EFGH
respectively, then it follows that the corresponding
lines (as stated in the answer above) would also be
similar.
Same applies to the four angles in the interior of the
trapezoids.
Number 2, Angle A equals Angle E
Angle B equals Angle F
Angle C equals Angle G
Angle D equals Angle H
Number 3,
If the scale factor between both figures is 2:3, then
for every length of a side in figure ABCD, the
corresponding side in figure EFGH would be
multiplied by 3/2.
Therefore if AD is 8cm, then EH equals 8 x 3/2
That gives us 12cm.
If GH is 6cm, then DC equals 6 x 2/3. That gives
us 4cm.
If AB is 3 times the length of DC, then AB equals 3
x 4, that gives us 12cm.
If AB is 12cm, then EF equals 12 x 3/2. That gives
us 18cm.
Take note that the shapes are both isosceles
trapezoids, o we have two sides of equal length, AD
and BC in the first figure and then EH and FG in the
other figure.
The first trapezoid has sides 8cm, 12cm, 8cm and
4cm. The perimeter is given as 8+12+8+4 32cm.
The second trapezoid has sides 12cm, 18cm, 12cm
and 6cm. The perimeter is given as 12+18+12+6=
48cm.
