Answer:
5 english students in each team
Step-by-step explanation:
So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.
Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups
- 128 math students ÷16 groups = 8 math students/group
- 80 english students ÷ 16 groups = 5 english students/group
The other way to solve this is to factor out common numbers between the two:
Answer:
first number= 19/5
second number= 2/5
Step-by-step explanation:
first number= a
second number= b
a+3b=5 equation 1
b+2a=8 equation 2
using equation 2 we have
b=8-2a
using equation 1 we have
a+3(8-2a)=5
a+24-6a=5
24-5=6a-a
19=5a
a=19/5 = first number
so using b=8-2a
we have
b=8-2(19/5)
b=8-(38/5)
b=2/5 = second number
Answer:
Hi how are you doing today Jasmine
(5,3) is your answer to the problem your welcome
Answer:10 wrong
Step-by-step explanation:
I am smart
Hope it helps :)