Answer:
1. 12 inches are in 1 foot, 48 inches of ribbon divided by 12 is 4 feet of ribbon.
2. Since there are 12 inches in 1 foot you multiply by 3 to 12 inches for 36 inches of ribbon.
3. When you're finding inches you need to divide but when you're finding feet you need to multiply.
4. His library card is 80 millimeters and since there are 10 millimeters in 1 centimeter you divide 80 by 10 to get 8 centimeters
5. His key chain is 35 millimeters long.
6. 3 quarts is bigger than 5 pints by 2 cups.
Picture contains the work you should show for questions 5 and 6.
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n(
) = 100
n(
) = 9
n(
) = 20
n(
) = 35
n(
) = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n() - n() + n()
= 72 - 35 - 29 + 9
= <em>17</em>
Answer:
A) 9 photos in each row
B) 14 rows in total
Step-by-step explanation:
Photos of People = 45
Photos of Landscapes = 18
Photos of Pets = 63
Jenny wants to arrange these photos in rows with only one kind of photos in each row and same number of photos in each row. We have to find the greatest possible number of photos in each row. For this we need to find the greatest common factor of 45,18 and 63. This would give us the greatest possible number of photos that can be placed in each row.
By observing the 3 numbers, we can tell that the greatest common factor of these 3 numbers is 9. So, Jenny can place 9 photos in each row.
So,
There will be:
45/9 = 5 rows with photos of people
18/9 = 2 rows of photos of landscapes
63/9 = 7 rows of photos of pets
So, total number of rows would be = 5 + 2 + 7 = 14 rows
8/10 or 4/5 is what makes up the remaining oceans
1 gallon = $3 so the ratio would be 1:3 where 1 would represent the gallon and 3 the price
