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3 years ago

Could someone please help me with this? Solution set of lx^2+mx+n=0 is...?

Mathematics

1 answer:

IgorLugansk [536]3 years ago

6 0

Answer:

Simplifying

lx2 + mx + n = 0

Solving

lx2 + mx + n = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1mx' to each side of the equation.

lx2 + mx + -1mx + n = 0 + -1mx

Combine like terms: mx + -1mx = 0

lx2 + 0 + n = 0 + -1mx

lx2 + n = 0 + -1mx

Remove the zero:

lx2 + n = -1mx

Add '-1n' to each side of the equation.

lx2 + n + -1n = -1mx + -1n

Combine like terms: n + -1n = 0

lx2 + 0 = -1mx + -1n

lx2 = -1mx + -1n

Divide each side by 'x2'.

l = -1mx-1 + -1nx-2

Simplifying

l = -1mx-1 + -1nx-2

Step-by-step explanation:

Hope this helped you!

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Hola alguien me puede decir cual es la respuesta

Arlecino [84]

Answer:

D, Option A $\sqrt{3}$

Step-by-step explanation:

CE = $\sqrt{3}$ (by using pythagorean theorem

A = 1/2 bh

A = 1/2 (2)( $\sqrt{3}$ ) = $\sqrt{3}$

8 0

3 years ago

Help me with this problem and show work please

monitta

Step 1: Subtract x from both sides.

1/3x +4− x =x −2− x

= -2/3 x +4 = -2

Step 2: Subtract 4 from both sides.

-2/3x + 4− 4 =−2− 4

-2/3x = -6

Step 3: Multiply both sides by 3/(-2).

( 3/-2 ) * (-2/3x ) = (3/-2) * (-6)

= 9

So , X=9

5 0

3 years ago

Help please? not sure about this

zimovet [89]

9514 1404 393

Answer:

72 kph

Step-by-step explanation:

The first sentence tells you the speeds are proportional. So, you can write the proportion ...

kph/mph = 120/75 = x/45

Multiplying by 45 gives x:

x = (45)(120/75) = 72

72 kph is 45 mph.

8 0

3 years ago

What is the equation of a circle with center of (4,2) passing through the point (7,2)

attashe74 [19]

Answer:

(x-4)^2 + (y-2)^2 = 3^2

(x-4)^2 + (y-2)^2 = 9 (simplified if needed)

Step-by-step explanation:

-Equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ where the center is (h, k) and the radius is $r^2$ .

-Place the center and the point onto that equation:

$(7-4)^2+(2-2)^2=r^2$

-Then, you solve:

$(7-4)^2+(2-2)^2=r^2$

$(3)^2+(0)^2=r^2$

$9 +0=r^2$

$9=r^2$

$\sqrt{9} =\sqrt{r^2}$

$3=r$

-So, the result is:

$(x-4)^2+(y-2)^2=3^2$

$(x-4)^2+(y-2)^2=9$ (simplified if needed)

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3 years ago

4. What key features of a quadratic graph can be identified and how are the graphs affected when the constants or coefficients a

natka813 [3]

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6 0

3 years ago

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