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alexandr402 [8]
3 years ago
12

What is 5/8 of 1/4? plz help

Chemistry
2 answers:
Verdich [7]3 years ago
5 0

5/8 + 1/4 = 0.875

Hope this helps! :)

Lena [83]3 years ago
5 0

5/8 of 1/4 as a decimal is 0.875 and as a fraction is 7/8. Hope this helps!!!

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Write the corresponding word equations for the reactions between;<br> (a) metals and water
Salsk061 [2.6K]

Answer:

M + H2O = MO + H2

Explanation:

When metals react with water they form oxides of the metal and hydrogen gas

7 0
4 years ago
Which of the following is a unit of density? = Mass / volume
krok68 [10]

Answer:

The correct answer is C.

Explanation:

To solve this problem, we should first recall possible units for mass and volume.  Mass can be represented with units of grams, kilograms, etc.  Volume has units of cubic meters, cubic centimeters, etc.

Therefore, since we know that density is mass divided by volume, the only answer that makes sense here is C. grams per cubic centimeter (where per signifies that grams are being divided by cubic centimeters).

Hope this helps!

7 0
3 years ago
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Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?
Dmitry [639]

Answer:

\fbox{3.81 \: grams}

Explanation:

First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.

5 0
3 years ago
(20 points) True or False: A benefit of fission and fusion reactions is that it takes very little mass to release large amounts
Arlecino [84]

Answer:

Hopefully its true, its seem like true. I think its true. Sorry if i'm wrong

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4 0
4 years ago
How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
Blizzard [7]

1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

#SPJ1

3 0
2 years ago
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