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Sergeeva-Olga [200]
3 years ago
8

On vacation, Aria went scuba diving in the Pacific Ocean for the very first time. She rose toward the surface of the water at a

steady speed for 4 minutes. She rose 36 meters in that time. What was her speed? HELP ME ASAP!!!!!!!!!!!!!
Chemistry
1 answer:
Readme [11.4K]3 years ago
8 0

Aria speed during scuba diving was 0.15 m/s.

Speed is the ratio of the distance travelled to the time taken. Speed is given by:

Speed = distance / time

Given that the distance travelled was 36 meters and the time was 4 minutes, hence:

Time = 4 minutes × 60 seconds per minute = 240 seconds

Speed = 36 m / 240 s

Speed = 0.15 m/s

Therefore Aria speed during scuba diving was 0.15 m/s.

Find out more at: brainly.com/question/22610586

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What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

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The fraction of the total atrazine can be calculated by the expression;

Total atrazine =C_w(\frac{g}{mL})*V_w(mL)+C_{(soil)}(\frac{g}{soil})*M_{(soil)}(gsoil)

Also; C_{(soil)}(\frac{g}{soil})= K_{oc}(\frac{mL}{gOC})*f_{oc} (\frac{gOC}{gsoil})*C_w(\frac{g}{mL})

NOTE THAT: K_{oc}( \frac{mL}{gOC})=K_{oc}\frac{L}{kgOC}

Total atrazine can now be calculated as:

C_w*0.4+K_{oc}f_{oc}C_w*0.75 = \frac{C_{soil}*M_{soil}}{Total atrazine}

=\frac{K_{oc}f_{oc}C_w*M_{soil}}{C_w*0.4+K_{oc}f_{oc}C_w*0.75} = \frac{0.75*K_{oc}f_{oc}}{0.4+K_{oc}f_{oc}*0.75}

= \frac{10^{2.52}*0.025*0.75}{0.4+10^{2.52}*0.025*0.75}

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Thus,the fraction of total atrazine that will be adsorbed to the soil = 0.94.

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