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4 years ago

Help!! Okay this is the question

Mathematics

2 answers:

Nuetrik [128]4 years ago

4 0

$125 per day that's the answer and I am right

Pavlova-9 [17]4 years ago

3 0

He earned 125 a day. If you divide the overall amount by the number of days he was working you get your answer.

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Ugo [173]

Answer:

10400

Step-by-step explanation:

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3 years ago

Read 2 more answers

Beth has 3/4 feet of ribbon to make bows it takes 1/12 a foot to make a bow how many bows can she make? create a visual fraction

Nesterboy [21]

She can make 9 bows.

6 0

4 years ago

What are the partial products for 3.2 x 0.6?

Lera25 [3.4K]

Answer:

This is a complete lesson with instruction & exercises for 5th grade about multiplying decimals by decimals. The interpretation for multiplying a decimal by a decimal is to think of it as taking a fractional part of a decimal number (the symbol × translates to "of"). The lesson compares multiplication by a decimal to scaling & shrinking a stick. Lastly, it shows the common shortcut to decimal multiplication (multiply as if there were no decimal points; the answer has as many decimals as the factors have in total.)

In the video below, I explain the rule for multiplying decimals (put as many decimal digits in the answer as there are in the factors.) I explain where this rule comes from, using fraction multiplication. The lesson continues below the video.

8 0

3 years ago

Mathematical Statistics with Applications Homework Help

photoshop1234 [79]

7.37:

a. W follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

$\displaystyle \sum_{i=1}^n\left(\frac{Y_i-\mu}{\sigma}\right)^2$

is chi-squared distributed with n d.f.. Here we have $\mu=0$ and $\sigma=1$ .

b. U follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

$\displaystyle \frac1{\sigma^2}\sum_{i=1}^n (Y_i-\overline Y)^2$

is chi-squared distributed with n - 1 d.f..

c. Y₆² is chi-square distributed for the same reason as W, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then U + Y₆² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.

7.38:

a. Notice that

$\dfrac{\sqrt 5 Y_6}{\sqrt W} = \dfrac{Y_6}{\sqrt{\frac W5}}$

and see definition 7.2 for the t distribution. Since Y₆ is normally distributed with mean 0 and s.d. 1, it follows that this random variable is t distributed with 5 degrees of freedom.

b. Similar manipulation gives

$\dfrac{2Y_6}{\sqrt U} = \dfrac{\sqrt4 Y_6}{\sqrt U} = \dfrac{Y_6}{\sqrt{\frac U4}}$

so this r.v. is t distributed with 4 degrees of freedom.

4 0

3 years ago

Part II: Free Response

Nastasia [14]

Answer:

Step-by-step explanation:

5 0

3 years ago