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madreJ [45]
3 years ago
10

What is the value of the expression below when y = 7? 2y^2 + 9y + 2 Help me!!!!!

Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

163

Step-by-step explanation:

2*(7^{2}) +9(7)+2

2*(49)+9(7)+2

98+63+2

=163

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If 4 electricians can wire some new houses in 20 days, how many electricians would be required to do the job in 10 days?
abruzzese [7]

Answer:

2

Step-by-step explanation:

20/2 = 10

4/2 = 2

8 0
2 years ago
i need help with this and i just copy and paste it.Beth's mother made some cookies. She put 4 cookies on each of 8 plates. Which
mr_godi [17]

Answer:

4x8=32

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A student charges $31.50 for 3 hours of babysitting. If the amount the student earns babysitting is proportional to the hours sp
vodomira [7]

Answer:

C) y is equal to 10.5x

Step-by-step explanation:

$31.50 is charged for <em>3  </em>hours so, for 1 hour we need to divide 31.50 by 3, which results in 10.50. So 1 hour of babysitting is $10.50

this is because x is equal to the number of hours they babysit. we do not know the actual so it is replaced with x

and y is equal to the sum of 10.5x because we multiply the number of hours worked, and the amount per hour.

7 0
3 years ago
Seven less than three-fifths times a number is less than or equal to eighteen. Which inequality BEST represents this situation?
denis-greek [22]
( \frac{3}{5} )*x - 7\leq 18
5 0
3 years ago
Read 2 more answers
Suppose that you believe that contractor 1 is twice as likely to win as contractor 3 and that contractor 2 is three times as lik
Ray Of Light [21]

Answer:

probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively

Step-by-step explanation:

assuming that there are no other contractors then:

probability that 1 , 2 or 3 win = 1

denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have

probability that 1 , 2 or 3 win = 1

probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1

2*P(X) + 3*P(X) + P(X) = 1

6*P(X) = 1

P(X) =1/6

then

-probability that contractor 1 wins = 2/6 (33%)

-probability that contractor 3 wins = 3/6 (50%)

-probability that contractor 3 wins = 1/6 (17%)

3 0
3 years ago
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