What is the value of the expression below when y = 7?<br> 2y^2 + 9y + 2<br><br><br> Help me!!!!!

Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and

TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33$

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$2.33 = \frac{X - 117}{4.33}$

$X - 117 = 2.33*4.33$

$X = 127.1$

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0

4 years ago

What happens to the decimal point when we multiply a whole number by 100?

baherus [9]

There is a similar shortcut for multiplying decimal numbers by numbers such as 10, 100, and 1000: Move the decimal point to the right as many places as there are zeros in the factor. Move the decimal point one step to the right (10 has one zero). Move the decimal point two steps to the right (100 has two zeros).

3 0

3 years ago

Read 2 more answers

The ratio of daisies to roses in a garden is 20:1. Does this garden have more roses or more daises in the garden

PtichkaEL [24]

Answer:

daisies

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

g A shopping center includes a grocery store and a drug store. One%E2%80%8B afternoon, a total of 200 people visited the shoppin

QveST [7]

Answer:

a) 179 people shopped at the grocery store or the drug store.

b) 21 people shopped at neither the grocery store nor the drug store

Step-by-step explanation:

I am going to treat these events as Venn sets.

I am going to say that:

Set A: Shopped at the grocery store

Set B: Shoped at the drug store.

121 shopped at the grocery store:

This means that $A = 121$

91 shopped at the drug store:

This means that $B = 91$

33 shopped at both businesses.

This means that $A \cap B = 33$

a) How many people shopped at the grocery store or the drug store?

This is

$A \cup B = A + B - (A \cap B)$

With the values given in the exercise.

$A \cup B = A + B - (A \cap B) = 121 + 91 - 33 = 179$

179 people shopped at the grocery store or the drug store.

b) How many people shopped at neither the grocery store nor the drug store?

179 of 200 shopped in at least one. So 200 - 179 = 21 shopped at neither.

21 people shopped at neither the grocery store nor the drug store

8 0

3 years ago

The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour

yan [13]

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

4 0

3 years ago

What is the value of the expression below when y = 7? 2y^2 + 9y + 2 Help me!!!!!