(10 1/2)/(3/8)
= (21/2)/(3/8) Convert to improper
= (21/2)*(8/3) Multiply by reciprocal of second
=(7/1)*(4/1) Cross reduce
=28 Multiply
Answer:
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Step-by-step explanation:
There's a quick, easy, sloppy way, and there's a good math way.
Here's the good math way:
If the integers are consecutive, then you can call them 'x', (x+1), and (x+2).
We know what their sum is, so let's add them up:
x + (x+1) + (x+2) = 336
x + x+1 + x+2 = 336
Combine the terms that are alike on the left side:
3x + 3 = 336
Subtract 3 from each side: 3x = 333
Divide each side by 3 : <u> x = 111</u>
The integers are<em> 111, 112, </em>and<em> 113</em> .
Step-by-step explanation:
Sum =2/3+4/10
=16/15
=1+1/15
Then
It's unreal
So Q hasn't any answer
Q is wrong
F(x) = x^2 +2*7x + 40
.. = (x^2 +2*7x +7^2) +(40 -7^2)
.. = (x +7)^2 -9
f(x) = (x +7)² -9
