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Studentka2010 [4]
3 years ago
9

If y varies directly as x and y is 12 when x is 1.2, what is the constant of variation for this relation?.

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
Hello,

y=k*x ; if x=1.2,y=12
==>12=k*1.2==>k=12/1.2==>k=10


Alex787 [66]3 years ago
4 0
From the question, we now that y is 12 when x is 1.2

in order to find out the constant of variation for this relation, we just need to substitute it to :

y = k x

12 = k 1.2

k = 12/1.2

k = 10

hope this helps
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Now, the set delivers 15 ggt or drops per mililiter. Let's calculate the total drops in the 51 mL.

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5 0
2 years ago
-2.8 f +0.9 f - 12 - 4
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In ΔABC, ∠B measures 35° and the values of a and b are 19 and 11, respectively. Find the remaining measurements of the triangle,
Anna35 [415]

Answer:

a)  ∠A = 82.2° , ∠C = 62.8° , c =   17.01

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

<em>By using sine rule </em>

<em></em>\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C}  = 2 R<em></em>

now we will use

\frac{a}{sin A} = \frac{b}{sin B}

\frac{19}{sin A} = \frac{11}{sin 35}

cross multiplication , we get

\frac{19 X sin 35}{11} = sinA

<em>sin A = 0.990</em>

<em>A = sin⁻¹( 0.990) = 82.2°</em>

<em> ∠A = 82.2°</em>

<u><em>Step(ii):-</em></u>

we know that ∠A +∠B +∠C = 180°

                         ∠C = 180° - ∠A -∠B

                          ∠C = 180° -82.2°-35°

                          ∠C = 62.8°

<u><em>Step(iii)</em></u>:-

<em>we will use formula</em>

<em></em>\frac{b}{sin B} = \frac{c}{Sin C}<em></em>

<em></em>\frac{11}{sin 35} = \frac{c}{Sin 62.8}<em></em>

\frac{11 X sin (62.8)}{sin 35} = C

<em>c =   17.01</em>

<u><em>Final answer</em></u>:-

<em> ∠A = 82.2° , ∠C = 62.8° , c =   17.01</em>

                         

4 0
3 years ago
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