Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval 
. So, the domain is (-8,3].
The values of the function lie in the interval 
. So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].
The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.
Gradient is the slope
So the slope of the line joining the points A(3,-5) and B(6,k) is 4
Slope of line joining two points = 
A(3,-5) and B(6,k) are (x1,y1) and (x2,y2)
slope =
slope = 
We know slope =4
Cross multiply and solve for k
k + 5 = 12
k = 7
The value of k = 7
Answer:
$2.29
Step-by-step explanation:
1. Divide $11.90 by 5.2
2. 11.90➗5.2 = 2.88 but you round the number so it will be 2.29
Hope this helps :)
Answer:
im so sorry but i only know the first one the answer in 5 from adding
Step-by-step explanation:
The answer is x=29
I hope this helps you
