The formula in solving the area of a square is Area = a² where "a" is for the length of the side. The area formula in solving a cube is Area = 6a² where "a" is for the length of its side.
Area of square = a²
64 = a²
a = 8 units
Area of cube = 6a²
64= 6a²
a = 3.27 units
The difference of side of the square and side of the cube is shown below:
Difference = 8 - 3.27
Difference = 4.73 units.
The answer is 4.73 units.
Answer:
1: 374cm
2: 248mm
3: 69m
I believe this is the right answer but I don't think the labels are correct
or, x=180
or,34=180
or,180-34
or x=146
Now,
or, y=146
or,18=146
or146-18
or, y=128
there is x is 34 and its all side angle is 180 degree So put x =180 and then put x value is 34 =180 and there is no values in front of 34 so there will be + and if +so in another side it will be - and then after put 180-34=146
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Step-by-step explanation:
1/3πr^2h
{(1/3)×(22/7)×2^2×6}m^3
[(1/3)×(22/7)×4×6)}m^3
{528/21}m^3
=25.1 m^3
NOTE:r=diameter divided by 2
