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Answer:
Step-by-step explanation:
we know that
The area of rectangle is equal to
we have
substitute the given values in the formula of area
Remember that
----> by completing the square
substitute
Simplify
The function is in polar coordinates.
When this is the case, to pass to rectagular (cartesian) coordinates you use:
x = r cos(theta)
y = r sin(theta)
Then,
x = [2cos(theta) + 2sin(theta)]cos(theta) =
= 2 [cos(theta)]^2 + 2sin(theta)cos(theta) = 2 [cos(theta)]^2 + sin(2theta)
y = [2cos(theta) + 2sin(theta)]sin(theta) =
= 2 cos(theta)sin(theta) + 2[sin(theta)]^2 = sin(2theta) + 2[sin(theta)]^2
Solving for 'y'
2x - 2y + 5 = 0
Add 2y on both sides
2x + 5 = 2y
Divide by 2 on both sides
y = x + 5/2
y = x + 2.5
Solving for 'x'
2x - 2y + 5 = 0
Subtract 2x on both sides.
-2y + 5 = -2x
Divide 2x on both sides
x = y - 5/2
x = y - 2.5
Must be : 2a+2 and 2a-2. Their sum is 2a and their difference is 4.
