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3 years ago

3/4 greater or less than 5/7

Mathematics

2 answers:

Mrrafil [7]3 years ago

5 0

3/4 = 0.75
5/7 = 0.71

3/4 is greater than 5/7

Mars2501 [29]3 years ago

4 0

3/4 is greater
hope it helps

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1. Evaluate -3x^3 -2y^2 when x=-5 and y =3

-Dominant- [34]

Answer:

357

Step-by-step explanation:

A) We replace x = - 5 and u = 3 into -3x^3 -2y^2

and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9

or -3x^3 -2y^2 = 375-18= 357

The answer is 357.

B) Replace h = -2 into h^2-3h+2

we have h^2-3h+2 = (-2)^2 -3*(-2) +2 = 4 +6 + 2= 12

The answer is 12

Have a good day.

8 0

4 years ago

What is the volume of a cone with radius 3.4 feet and altitude 4.8 feet?

Delvig [45]

Answer:

V≈58.11ft³

Step-by-step explanation:

that is the answer because you are trying to find the volume.

8 0

3 years ago

Please explain whether it's true or false? Thanks

svlad2 [7]

15. true 16. false in my coculations.

7 0

3 years ago

The measure of angle zero is 600°. The point XY corresponding to zero on the unit circle is

Andrej [43]

<u>Answer:</u>

$x= -\frac{1}{2}\\\\ y= -\frac{\sqrt{3}}{2}$

<u>Step-by-step explanation:</u>

We are given that the measure of angle θ is 600° and we are to fin the point (x, y) corresponding to angle θ on the unit circle,

We know that the x,y coordinates in the unit circle are the cosine and sine ratios, respectively.

θ = 600

1 unit circle= 360°

It means that 600° corresponds to 600° - 360° = 240°.

So, θ = 360° + 240°

180° < 240° < 270° (this tells that the point is in the third quadrant and its coordinates are negative)

240° - 180° = 60° (using the supplementary angles to find the sin and cos) $\sin 60^\circ = \frac{\sqrt{3}}{2}\\\\\cos 60^\circ= \frac{1}{2}$

Therefore, the x-coordinate is the cos of the given angle while y-coordinate is the sine of the given angle and the coordinates are:

$x= -\frac{1}{2}\\\\ y= -\frac{\sqrt{3}}{2}$

3 0

3 years ago

Find the area. The figure is not drawn to scale

poizon [28]

Answer:

96 square inches.

Step-by-step explanation:

From given picture we see that

BC=8 in

AD=10 in

Given that

AD=AB

Then AB=10 in

Apply Pythagorean theorem in triangle ABC to find AC

$(hypotenuse)^2=(base)^2+(perpendicular)^2$

$(AB)^2=(BC)^2+(AC)^2$

$(10)^2=(8)^2+(AC)^2$

$100=64+(AC)^2$

$100-64=(AC)^2$

$36=(AC)^2$

take square root

$6=AC$

Then area of triangle ABC $=\frac{1}{2}\left(base\right)\left(altitude\right)$

$=\frac{1}{2}\left(8\right)\left(6\right)=24$

There are total 4 congruent triangles.

Then total area of the given figure = 4(24)=96 square inches.

7 0

3 years ago