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MArishka [77]
3 years ago
15

a biker travel 5ft in .05seconds. At that same rate of speed , how far will the biker travel in 1minute?

Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0

Biker's rate is:

v = 5/0.5

v = 10 ft per sec

t = 1 min = 60 sec

d = the distance the biker travels in 1 minute

v = d/t

d = v*t

d = 10*60

d = 600 ft

The biker travels 600 feet in 1 minute

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Answer:

<-3,4>

<0,-5>

Step-by-step explanation:

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3|-w| = 3|w| = 15

|w| = \frac{15}{3}

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Then |w| = \sqrt{(1)^{2}+(-9)^{2}}=\sqrt{1+81}=\sqrt{82}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-3,4>

Then |w| = \sqrt{(-3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5 .

Therefore this is possible.

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Then |w| = \sqrt{(4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-5,-3>

Then |w| = \sqrt{(-5)^{2}+(-3)^{2}}=\sqrt{25+9}=\sqrt{34}\neq5 .

Therefore this is not possible.

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Then |w| = \sqrt{(0)^{2}+(-5)^{2}}=\sqrt{0+25}=\sqrt{25}=5 .

Therefore this is possible.

(NOTE : if z vector is represented by <x,y> then |z| = \mathbf{\sqrt{x^{2}+y^{2}}} )

4 0
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