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vazorg [7]
3 years ago
8

PLEASE HELP THIS IS TIMED WHAT IS THE FOLLOWING SUM FIRST ONE IS QUESTION THE REST ARE CHOICES

Mathematics
1 answer:
murzikaleks [220]3 years ago
5 0
\sqrt[3]{125x^{10}y^{13}}+\sqrt[3]{27x^{10}y^{13}}\\\\\sqrt[3]{125*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}+\sqrt[3]{27*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}\\\\\\\sqrt[3]{125}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}+\sqrt[3]{27}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}\\\\\\5*x*x*x*\sqrt[3]{x}y*y*y*y*\sqrt[3]{y}+3*x*x*x*\sqrt[3]{x}*y*y*y*y*\sqrt[3]{y}\\\\5x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}+3x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}\\\\5x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}+3x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{xy}
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Donnell and Maria are both members of a populationand a simple random sample is being conducted. If the chance of Donnell being
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289/290

Step-by-step explanation:

Given that the chance of Donnell being selected is 1/290

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Read 2 more answers
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