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vazorg [7]
4 years ago
8

PLEASE HELP THIS IS TIMED WHAT IS THE FOLLOWING SUM FIRST ONE IS QUESTION THE REST ARE CHOICES

Mathematics
1 answer:
murzikaleks [220]4 years ago
5 0
\sqrt[3]{125x^{10}y^{13}}+\sqrt[3]{27x^{10}y^{13}}\\\\\sqrt[3]{125*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}+\sqrt[3]{27*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}\\\\\\\sqrt[3]{125}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}+\sqrt[3]{27}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}\\\\\\5*x*x*x*\sqrt[3]{x}y*y*y*y*\sqrt[3]{y}+3*x*x*x*\sqrt[3]{x}*y*y*y*y*\sqrt[3]{y}\\\\5x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}+3x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}\\\\5x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}+3x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{xy}
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After 15% discount an item cost $22.27 what was the original price?
musickatia [10]
Orig - .15 * orig = 22.27
.85 * orig = 22.27
Original price = 26.20

6 0
4 years ago
Read 2 more answers
What can you conclude about the paths of the skaters? There is no chance that the skaters will hit each other. The skaters' path
Pie

Answer:

C: The skaters are traveling on the same path, but possibly in different directions.

Step-by-step explanation:

edge 2021-2022

5 0
3 years ago
Write an equation of the line that is perpendicular to the line y = 1 2 x + 8 that passes through the point (4,6)
Katen [24]

Answer:

\large\boxed{y=-2x+14}

Step-by-step explanation:

\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=\dfrac{1}{2}x+8\to m_1=\dfrac{1}{2}.\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2.\\\\\text{The equation of the searched line:}\ y=-2x+b.\\\\\text{The line passes through }(4,\ 6).

\text{Put thecoordinates of the point to the equation.}\ x=4,\ y=6:

6=-2(4)+b\\\\6=-8+b\qquad\text{add 8 to both sides}\\\\b=14

6 0
4 years ago
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what is the area of a figure what is the area of a figure with a 16 inch base a 10 inch base and a height of 8 in on the left an
tensa zangetsu [6.8K]
So I’m thinking of this as two triangles. So I would do 16x8/2 which equals 64 and 10x6/2 which equals 30. So my guess is that the area is 94in^2. Hope this helps you out!
3 0
3 years ago
Which are the coordinates of the midpoint of JK with endpoints J(-7, -1) and K(13, -6)?
dsp73
The x coordinate of J is -7. The x coordinate of K is 13. The x coordinates add up to -7+13 = 6. Divide this result in half to get 6/2 = 3. Therefore, the midpoint has an x coordinate of 3.

The y coordinate of J is -1. The y coordinate of K is -6. The y coordinates add up to -1+(-6) = -7. Divide this result in half to get -7/2. Therefore, the midpoint has a y coordinate of -7/2.

This is why the final answer is choice D) (3, -7/2)
7 0
3 years ago
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