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Korvikt [17]
3 years ago
12

A professor using an open source introductory statistics book predicts that 60% of the students will purchase a hard copy of the

book, 25% will print it out from the web, and 15% will read it online. At the end of the semester he asks his students to complete a survey where they indicate what format of the book they used. Of the 126 students, 71 said they bought a hard copy of the book, 30 said they printed it out from the web, and 25 said they read it online. State the hypotheses for testing if the professor’s predictions were inaccurate.
Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

See explanation below

Step-by-step explanation:

We need to define the null hypothesis and the alternative hypothesis.

The null hypothesis is the hypothesis that states that the population results are actually what they claimed to be.

So, in this case, the null hypothesis (H₀) would be:<u> P(student buys a hard copy) = 0.60 P(student prints book from the web) = 0.25, P(student reads book online) = 0.15</u>

The alternate hypothesis states that the results were not the expected ones, in this case, any alternate hypothesis with different probabilities of any of the three cases will do.

<u>Hₐ= The percentages of students for any of the three cases is different (either greater or lower)</u>

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NEED HELP PLEASE!
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Answer:

(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16

Step-by-step explanation:

Complex numbers identity:

The complex numbers identity is:

i^2 = -1

Square of the sum:

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In this question:

(x + (3+5i))^2

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2 years ago
Dans un magasin de sport, une paire de chaussures coûte 69,30 €, après une remise de 30 %. Quel était le prix initial (avant la
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The computation of the original price (before the rebate)  of this pair of shoes is shown below:

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It is required to find the maximum height of the arrow. For maximum height, \dfrac{dh}{dt}=0.

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\dfrac{d(-16t^2 +80t + 25)}{dt}=0\\\\-32t+80=0\\\\t=\dfrac{80}{32}\\\\t=2.5\ s

Put t = 2.5 s in equation (1). So,

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So, the maximum height of the arrow is 125 feet.

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