Question

The pythagorean theroy if a 4=a 8=b what is c

Answer 1

If a = 4 and b = 8 are the legs and c is a hypotenuse then:

$a^2+b^2=c^2$

Substitute:

$c^2=4^2+8^2\\\\c^2=16+64\\\\c^2=80\to c=\sqrt{80}\\\\c=\sqrt{16\cdot5}\to c=4\sqrt5$

If a = 4 and c are the legs and b = 8 is hypotenuse, then:

$a^2+c^2=b^2$

Substitute:

$4^2+c^2=8^2\\\\16+c^2=64\ \ \ |-16\\\\c^2=48\to c=\sqrt{48}\\\\c=\sqrt{16\cdot3}\to c=4\sqrt3$

Answer 2

A^2+b^2=c^2
4^2+8^2=c^2
16+64=c^2
c^2=80
c=the square root of 80 or about 8.9442719......