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3 years ago

If i was born april 16th 1991 how old would i be?

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

You would be 26 im pretty sure

Elza [17]3 years ago

6 0

<span>You would be 26 years, 3 weeks, and 6 days old

hope this helps</span>

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A complex number z_1z 1 z, start subscript, 1, end subscript has a magnitude |z_1|=6∣z 1 ∣=6vertical bar, z, start subscript

aliina [53]

Answer:

The answer is " $\bold{9.19- 9.19\ i}$ "

Step-by-step explanation:

When the value of $z_1$ has the following properties:

$\to |z_1| =13$

$\theta = 315^{\circ} \\\\ = 1.75 \pi\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \ (\pi = 180^{\circ})$

Calculating the value of $z_1$ :

$= 13 \times [ \cos(1.75 \pi ) + i \sin(1.75 \pi) ] \\\\= 13 \times[\cos(1.75 \pi - 2\pi ) + \ i \sin(1.75 \pi - 2\pi )]\\ \\= 13 \times [\cos(-0.25 \pi ) +\ i \sin(-0.25 \pi) ]\\\\= 13 \times [0.707106781 - 0.707106781]\\\\ =9.19 - 9.19\ i \\\\$

3 0

3 years ago

How do you write 2.375 x 10^-7 in standard form? (10 to the power of -7) PLEASE HELP!

slava [35]

0000002375 is the answer

6 0

4 years ago

9w-4w+6<1+5w supposed to combine like terms

Mariana [72]

Answer/Step-by-step explanation:

Given:

$9w - 4w + 6$ < $1 + 5w$

To solve, collect like terms.

Subtract 5w from both sides

$9w - 4w + 6 - 5w$ < $1 + 5w - 5w$

$9w - 4w - 5w + 6$ < $1$

$6$ < $1$ (incorrect)

The inequality given has no solution or an information is missing.

6 0

3 years ago

in Joell's math class there are 8 girls and 17 boys. Based on this ratio how many students would be boys in the total school of

yan [13]

So the total number of students equals 8+17 = 25 students
Proportionally:
$\frac{17}{25} = \frac{x}{100}$

Thus,
$x = \frac{17*100}{25} = 68$ boys out of the 100 students.

4 0

3 years ago

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He formula for density is given by , where p is density, M is mass and V is volume. If a substance has a mass of 27.82 grams and

Vera_Pavlovna [14]

Answer:

p = [27.82] ÷ [3.6]

p = 7.727·

p = 7.728 (3dp)

The answer is B)

Step-by-step explanation:

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3 years ago

Read 2 more answers