Answer:
f(t) = 4 - 3t + 2t^2
Step-by-step explanation:
Given:
f(t) = a + bt + ct^2
Differentiate w.r.t. "t"
f'(t) = b + 2ct
1) f(1) = 3
a + b +c = 3...........1)
2) f(2) = 6
a + 2b + 4c = 6.........2)
3) f'(1) = 1
b + 2c = 1 ...............3)
Solving above three simultaneous equations:
a = 4
b = -3
c = 2
Therefore equation becomes:
f(t) = 4 + (-3)t + (2)t^2
Answer:
$5.65
Step-by-step explanation:
1.20x0.50=0.60
1.50x2.50=3.75
0.60+3.75=4.35
10.00-4.35
5.65
12 times 2 ..............................
Ok, so you have a right angle, a given angle, and a given side for the left triangle. We are going to call angle 47° angle A. So angle A=47°, the side connecting the two triangles is directly opposite A making it side "a". We are calling the right angle C and the hypotenuse (the longest side which is 11) "c". So, Sin A=a/c and since we don't have "a" we multiply both sides by "c" changing it to (c Sin A)=a. 11•Sin(47°)=a
11•(0.7313537016)=a
8.044890718=a
