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3 years ago

Expression of 450 or fewer heads comes up when flipping a coin 500 times

1 answer:

5 0

You expect to get heads 250 times and tails 250 times, So, if this is the case and you flip your coin 500 times, you would most likely get heads 257 times and tails 243 times.

Does that make sense?

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Solve the equation. 19 + n = 30 19+n=3019, plus, n, equals, 30 n = n=

Eva8 [605]

Answer:

n =11

Step-by-step explanation:

3 0

3 years ago

Birthdays of hockey players: In Malcolm Gladwell’s book "Outliers" he shares the work of Canadian psychologist Roger Barnsley, w

alexgriva [62]

Answer:

The P-value is 0.009.

Step-by-step explanation:

We are given that after debating whether this set of hockey players can be viewed as a random sample of hockey players, they decide to run a hypothesis test anyway to practice finding the P‐value.

We are given that the following hypothesis below;

Null Hypothesis, $H_0$ : p = 0.25

Alternate Hypothesis, $H_A$ : p > 0.25

Now, the test statistics that was used here for the above hypothesis would be;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

Also, the test statistics given to us is 2.37.

SO, the P-value of the test statistics is given by the following formula;

P-value = P(Z > 2.37) = 1 - P(Z $\leq$ 2.37)

= 1 - 0.99111 = 0.00889 ≈ 0.009

The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.99111.

Therefore, the required P-value is 0.009.

6 0

3 years ago

Geom help please will give brainliest

podryga [215]

Try this option:

1] P(S)=0.84;

2] P(S or C, but not both)=0.4;

3] P(C)=0.76;

4] P(S∪C)=0.6;

5] P(C, but not S)=0.16;

6] P(S∩C)=1.00.

7 0

3 years ago

Read 2 more answers

A rectangular box has volume 10 cubic meters. the base of the box is a square. the top and the base of the box are made from mat

allsm [11]

200 times 20 qnd ten then 30 if you want then go from there

3 0

4 years ago

X + 3y = −1 2x + 2y = 6

hram777 [196]

$\left\{\begin{array}{ccc}x+3y=-1\\2x+2y=6&|divide\ both\ sides\ by\ (-2)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x+3y=-1\\-x-y=-3\end{array}\right}\\.\ \ \ \ \ \ \ \ \ 2y=-4\ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \ \ \fbox{y=-2}\\\\subtitute\ the\ value\ of\ y\ to\ the\ equation\ x+3y=-1\\\\x+3\cdot(-2)=-1\\x-6=-1\ \ \ \ |add\ 6\ to\ both\ sides\\\fbox{x=5}\\\\Answer:\boxed{x=5\ and\ y=-2}$

5 0

4 years ago