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charle [14.2K]
3 years ago
14

3x + 3(x + y) ? Help!

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

=6x+3y

Step-by-step explanation:

3X+3(X+Y)

Distribute:

=3X+(3)(X)+(3)(Y)

=3X+3X+3Y

Combine Like Terms:

=3x+3x+3y

=(3x+3x)+(3y)

=6x+3y

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Add -2 on the both sides
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According to these three facts, which statements are true?
Yanka [14]
Q1) We have the following statements:

<span>1. Circle W has center (−3, 0) and radius 8.

We can write this statement as the following equation:

</span>(x-h)^2+(y-k)^2=r^2 \therefore (h,k)=(-3,0) \ and \ r=8 \\ \\ \therefore (x+3)^2+y^2=64
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The graph of this equation is shown in Figure 1.

</span><span>2. Circle V is a translation of circle W, 2 units down.

To do this translation we add two units to the y-coordinate, so:

</span>(x+3)^2+(y+2)^2=64
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The graph is shown in Figure 2.

</span><span>3. Circle V is a dilation of circle W with a scale factor of 2.

To do this dilatation we multiply both the center and the radius by the scale factor of 2, thus:

</span>(x+3)^2+y^2=64 \\ (h,k)=(-3,0) \\ (h_v,k_v)=2\times (-3,0)=(-6,0) \ and \ r_v=8\times2=16 \\ \\ (x+6)^2+y^2=256
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Q1.1) </span><span>The center of circle V is (−5, 0).

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Q1.2) 
</span><span>Circle V and circle W are similar.

Since all circles have the same shape even though they may be different sizes, then all circles are similar. Therefore, it is true that circle V and circle W are similar.

Q1.3) 
</span><span>The radius of circle V is 16.

From the statement 3 we can affirm that this is true. By applying the dilatation </span><span>with a scale factor of 2 we find out that the radius of the new circle is in fact equal to 16.

Q1.4) </span>Circle V and circle W have the same center. 

From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0). On the other hand, the center of circle W is (-3, 0). From this, it follows that this statement is false.

Q2) Suppose x is any positive number.

We have two concentric circles as follows:

x\ \textgreater \ 0 \\ \\ Circle \ 1: Center \ (0,0) \ and \ radius \ 2x \\ \\ Circle \ 2: Center \ (0, 0) \ and \ radius \ 10x<span>

Q2.1) Why is circle 1 similar to circle 2?
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If we perform a dilatation, that is, a </span>resizing of one circle, centered on the shared center, until both circles overlap, it will be true that the circles will always overlap no matter what size they are, thus, they are similar. In fact, as we said in above all circles are similar. 

Q2.2) 
<span>Circle 2 is a dilation of circle 1 with a scale factor of 0.2.

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If we dilate this circle </span><span>with a scale factor of 0.2 then:

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<span>Q2.3) Circle 2 is a dilation of circle 1 with a scale factor of 5.

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</span>x^2+y^2=4

Circle \ 1: x^2+y^2=4 \\ \\ Dilatation: \\ (h,k)=(0,0) \\ (h_v,k_v)=5\times (0,0)=(0,0) \ and \ r_v=5\times 2=10 \\ \\ Circle \ 2:x^2+y^2=100

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