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Answer:
|2x - 5| = 4
Solve for the negative and positive expressions:
2x - 5 = 4
2x = 9
x = 9/2
------------
-(2x - 5) = 4
-2x + 5 = 4
-2x = -1
x = 1/2.
Therefore, the solutions are x = 1/2 and 9/2.
Given:
Consider the discount percent and SP are given.
To find:
The MP.
Solution:
Let x% be the discount percent Then
Multiply both sides by 100.
Divide both sides by 
.
Therefore, the formula for MP is 
, where x is the discount percentage.
Answer:
Please find attached the graph of the following function;
Step-by-step explanation:
We note that the function is linear from x = 2 to just before x = 0
The linear relationship of the function f(x) with x changes just before x = 0
At x = 0, the value of f(x) is indicated as 1
From just after x = 0, the function is a straight horizontal line y = 3
The function also changes value immediately after x = 0 to the line y = 3
The areas where the function is defined are shown in continuous lines
Answer: Answer:Median: 10.5Lower quartile: 4Upper quartile: 16Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 12 (even)Median = Mean of (6)th and (7)th observations = 10 + 11 divided by 2 = 21/2 = 10.5Therefore the median is 10.5.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 16Question 2.the lengths of 10 pencils, in centimeters:18, 15, 4, 9, 14, 17, 16, 6, 8, 10Type below:_________________Answer:Median: 12Lower quartile: 4Upper quartile: 18Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 10 (even)Median = Mean of (5)th and (6)th observations = 10 + 14 divided by 2 = 24/2 = 12Therefore the median is 12.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 18Question 3.Make a box plot to display the data set in Exercise 2.Type below:_________________Answer:The above box plot represents the lower and upper quartiles, the median.Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Question 4.The numbers of students on several teams are 9, 4, 5, 10, 11, 9, 8, and 6. Make a box plot for the data.Type below:_________________Answer: Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Therefore the lower and upper quartiles are 4 and 11 respectively.Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 8 (even)Median = Mean of (4)th and (5)th observations = 8 + 9 divided by 2 = 17/2 = 8.5Therefore the median is 8.5.
Step-by-step explanation:
