The factored form of the polynomial function is y(x) = (x + 3)²(x - 4)(x - 2)
<h3>How to determine the factored form?</h3>
The given parameters are:
- Leading coefficient, a = 1
- Zeros = -3, -3, 4, and 2.
Rewrite the zeros as:
x = -3, x = -3, x = 4 and x = 2
Set the zeros to 0
x + 3 = 0, x + 3 = 0, x - 4 = 0 and x - 2 = 0
Multiply the zeros
(x + 3) * (x + 3) * (x - 4) *(x - 2) = 0
Express as a function
y(x) = a(x + 3) * (x + 3) * (x - 4) *(x - 2)
Substitute 1 for a
y(x) = (x + 3)²(x - 4)(x - 2)
Hence, the factored form of the polynomial function is y(x) = (x + 3)²(x - 4)(x - 2)
Read more about polynomials at:
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Step-by-step explanation:
3x+12=45
3x=45-12
3x=33
3x/3=33/3
x=11
Step-by-step explanation:
2x-5=2x-6. First you collect like terms
2x-2x=-6+5
0=-1
This statement is false 0≠-1
Answer:
Step-by-step explanation:
With reference < H
perpendicular (p) = 12
base (b) = 5
so now
tangent of < H
= p / b
= 12 / 5
hope it helps :)
Answer:
Seeing that we have a shared hypotenuse and two sides that are congruent, the theorem that we can use is the HL Theorem.
Step-by-step explanation:
mark brainliest :)