Answer:
Step-by-step explanation:
there is a factoring rule where
So,
a = x
b = y + z
2x-2 must be zero or greater, since we cannot have a negative quantity under the radical sign (unless we allow for imaginary roots).
Solving 2x-2≥0, we get x-1≥0, or x≥1. x must be equal to or greater than 1.
16 - 16, so the answer to the 2nd problem is the fourth one: x=4.
1st term = -10
2nd term = -6
3rd term = -2
4th term = 2
5th term = 6
6th term = 10
7th term = 14
The reason how I got 14 for the 7th term is because, i added 4 to each term.
Hope this helps!
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.</span>
11/2 / 3 = 11/6 pounds per friend
divide 11/2 pounds by 3 in order to get answer
