The answer is the range. The outliner is anything that “lies outside.” Range is the highest#-lowest#. So 78-28 = 50, which is not close the numbers that occurred most often (in this case, the #s in the 30s).
9514 1404 393
Answer:
18
Step-by-step explanation:
Solve the first for a, then substitute into the second.
a = 27/(5b^2)
Then ...
(27/(5b^2))^2·b = 135
27^2/(5^2·135) = b^3 = 27/125
b = ∛(27/125) = 3/5
a = 27/(5(3/5)^2) = 15
__
The expression of interest is ...
a +5b = 15 + 5(3/5) = 15 +3
a +5b = 18
Answer:
25
Step-by-step explanation:
<ABD=<BDC
Check it out
Answer:
90/200
Step-by-step:
Kahn Academy marked it correct
Answer:
With alpha 0.95 and 8 degrees of freedom χ²= 2.73
And with alpha 0.05 and 8 degrees of freedom χ²=15.51
Step-by-step explanation:
The significance level ∝ = 1- 0.9 = 0.1
But we need the area of the middle so we divide this significance level with 2
so that we get exactly the middle area .
Dividing 0.1/2= 0.05
So we will have two values for chi square
One with 0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.
So with alpha 0.95 and 8 degrees of freedom χ²= 2.73
And with alpha 0.05 and 8 degrees of freedom χ²=15.51
This can be shown with a graph.