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3 years ago

Eric practice for his piano recital 3/4 hour every day last week. How many hours did Eric practice last week

Mathematics

1 answer:

Nikolay [14]3 years ago

7 0

Answer: 5.25

Step-by-step explanation: there are 7 days in a week so if he practiced everyday for a week he practiced 3/4 hours for 7 days straight, so 3/4 × 7= 5.25

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Determine the following:

dolphi86 [110]

Answer:

a) P(X = 0) = 0.5997

b) P(X = 9) = 0.0016

c) P(X = 8) = 0.0047

d) P(X = 5) = 0.4018

Step-by-step explanation:

These following problem are examples of the binomial probability distribution.

Binomial probability

Th binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

(a) for n = 4 and π = 0.12, what is P(X = 0)?

$P(X = 0) = C_{4,0}.(0.12)^{0}.(0.88)^{4} = 0.5997$

(b) for n = 10 and π = 0.40, what is P(X = 9)?

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

(c) for n = 10 and π = 0.50, what is P(X = 8)?

$P(X = 8) = C_{10,8}.(0.5)^{8}.(0.5)^{2} = 0.0047$

(d) for n = 6 and π = 0.83, what is P(X = 5)?

$P(X = 5) = C_{6,5}.(0.83)^{5}.(0.17)^{1} = 0.4018$

3 0

3 years ago

Area and circumference of this circle

faust18 [17]

Answer:

Step-by-step explanation:

Given: The radius is 6 cm

To find the area + circumference we need to use 2 formulas:

Area: pi* radius^2

Circumference: 2*pi*r

First we can do the area

I will use "pi" for pi instead of 3.14

pi * 6^2

= 36 pi

The area is 36 pi

Next, circumference

2 * pi *r

2*pi*6

= 12 pi

So the area is 36 pi, and the circumference is 12 pi

5 0

2 years ago

NEED HELP ASAP Given G (-6,5) and H (2, -7), what is the length of GH

lesya692 [45]

$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

We have given that the coordinates of the end point G and H are ( -6,5) and ( 2, -7 )

$\bold{\underline{To \: Find :- }}$

We have to find the length of GH

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

According to the distance formula, we get :- 

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

Here, x1 = -6 , x2 = 2 and y1 = 5 , y2 = -7

Subsitute the required values in the above formula 

$\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}$

$\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}$

$\sf{Distance\:GH=√(-8)^2+(12)^2}$

$\sf{ Distance \:GH =√64 + 144 }$

$\sf{ Distance \:GH =√ 208}$

$\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}$

$\sf{ Distance \:GH = 4√13}$

$\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}$

3 0

2 years ago

In June 2005, a CBS News/NY Times poll asked a random sample of 1,111 U.S. adults the following question: "What do you think is

Shtirlitz [24]

Answer:

The appropriate null hypothesis is $H_0: p = 0.25$

The appropriate alternative hypothesis is $H_1: p < 0.25$

Step-by-step explanation:

Exactly a year prior to this poll, in June of 2004, it was estimated that roughly 1 out of every 4 U.S. adults believed (at that time) that the war in Iraq was the most important problem facing the country.

At the null hypothesis, we test if the proportion is still the same, that is, of $\frac{1}{4} = 0.25$ . So

$H_0: p = 0.25$

We would like to test whether the 2005 poll provides significant evidence that the proportion of U.S. adults who believe that the war in Iraq is the most important problem facing the U.S. has decreased since the prior poll.

Decreased, so at the alternative hypothesis, it is tested if the proportion is less than 0.25, that is:

$H_1: p < 0.25$

3 0

3 years ago

for every weekend that mia does her household chores her mother gives her $9.for how many weekends does mia have to do her chore

allsm [11]

So, we'll say Mia gets $4.50 a day, since a standard weekend is two days, therefore adding up to $9 a weekend. So if Mia were to do her chores for 4 weekends, she'd have a total of $36 but not $40. So if she were to work an extra weekend, so 5 weekends, she'd have a total of $45. So you can say 5 weekends in order to earn more than $40.

7 0

2 years ago