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Cerrena [4.2K]
3 years ago
10

9 11 13 15 17……finding the nth term of a sequence

Mathematics
2 answers:
dangina [55]3 years ago
6 0
The pattern seems to be adding two to the previous number to get the next term. so 17 + 2 is 19, 19 + 2 is 21, 21 + 2 = 23, 23 + 2 = 25 the 9th term is 25
andre [41]3 years ago
5 0
1.9
2.11
3.13
4.15
5.17
6.19
7.21
8.23
9.25
You might be interested in
X(7 - x) > 8 A. 8 B.2 C. -1 D.0
Elodia [21]
=7x-x^2>8
0=7x-x^2-8
0= -x^2 + 7x -8
0=(x^2 + 8x)-(x - 8)
0=x(x + 8)-1(x +8)
0=(x-1)   0=(x+8)
x=1          x= -8






3 0
3 years ago
During the school year, each student planted 2 x 10^2 trees as part of a community service project. If there are 3.5 x 10^3 stud
amm1812

Answer:

Total number of trees planted =  7\times 10^{5} trees

Step-by-step explanation:

Trees planted by each student = 2\times 10^2

Total number of students = 3.5\times 10^3

Using unitary method to find total number of trees planted by all the students in school.

1 student plants = 2\times 10^2 trees

3.5\times 10^3 student would plant = (2\times 10^2)\times (3.5\times 10^3)

We apply the product rule of exponents to multiply [a^xa^y=a^{x+y}]

⇒ (2\times 3.5)\times(10^2\times 10^3)

⇒ 7\times 10^{2+3}

⇒ 7\times 10^{5} trees

Total number of trees planted =  7\times 10^{5} trees

4 0
4 years ago
Which invention allowed computers to be smaller?
swat32

Answer:

laptop/phone

As the computer advanced, transistors were invented. They were smaller and allowed the computers to become smaller than ever. Slowly, the size of the computers decreased as more and more pieces were invented.

Step-by-step explanation:

4 0
3 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
Can someone pls pls help me?
Neko [114]

Answer:

(-3.5,-2)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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