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kkurt [141]
3 years ago
9

In a recreation park a children's slide is 27 feet long and makes an able of 39 degrees with the ground. Its top is reached by a

ladder 18 feet long. What is the angle of inclination of the ladder.
Mathematics
1 answer:
timurjin [86]3 years ago
3 0
Each angle on a triangle would add up to 180 degrees. Since a ladder goes straight up, that angle would be 90 degrees. If you add that with the 39 degree angle, you'd get 129. Subtract that from 180 and you have your answer.
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An item is regularly priced at $80. Juan bought It at a discount of 20% off the regular price. How much did Juan pay?
Gnesinka [82]
Hello there! So, the item has a 20% discount, but Juan still had to pay 80% for the item. To find the amount he paid, all you have to do is multiply the price by the percentage. We multiply by 80%, because he still had to pay the portion of the price. 80 * 80% (0.8) is 64. The. Juan paid $64.
3 0
3 years ago
According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
bogdanovich [222]

Answer:

Seven-thirds

Step-by-step explanation:

The give equation is f(x)=9x^8+9x^6-12x+7.

The leading coefficient is 9

The constant term is 7

According to the rational root theorem, the ratio of factors the constant terms to that of the coefficient of the leading term are all possible rational roots of the given polynomial.

Base on this theorem, \frac{7}{3} or seven thirds is a potential root because the numeration is a factor of 7 and the denominator is a factor of 9.

5 0
3 years ago
Read 2 more answers
25 pound x 41.000 pounds
Crank
1,025 lbs I think that s the answer
7 0
3 years ago
Help me solve this question please.
AleksandrR [38]
The answer is D. 9(y+3) and 27 + 9y
You would distribute the 9 to both the 3 and the y. 
6 0
3 years ago
Read 2 more answers
Find a and b such that gcd(a, b) = 14, a > 2000, b > 2000, and the only prime divisors of a and b are 2 and 7.
choli [55]

Answer:

a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

a = 2^\alpha.14 \\b = 7^\delta.14

All we have left to do is find the possible values for \alpha and \delta so that a>2000 \ , b>2000 and that only happens if \alpha\geq 8 and \delta\geq 3

8 0
3 years ago
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