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bearhunter [10]
3 years ago
13

Cual número entero tiene 2×5 como factorizacion prima​

Mathematics
2 answers:
harina [27]3 years ago
4 0

Answer:

The expression is not factorable with rational numbers.

Step-by-step explanation:

Sophie [7]3 years ago
3 0

Answer:

10

Step-by-step explanation:

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Step-by-step explanation:

3 0
3 years ago
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Please help me branniest <br> Explain answers
Nana76 [90]

when a number is raised to two powers, the first step is to multiply the two powers together:

1/3 * 3 = 1

Now you have 5^1 which equals 5.


The answer is B. 5



7 0
3 years ago
All currently has $25. He is going to start saving $5 every week
sergij07 [2.7K]

Answer:

I believe the answer is b  

Step-by-step explanation: I think the answer is b because he gets $5 every week and he already has $25 the only thing we dont know is the weeks and you multiply 5 by the weeks so, 5(how much he gets each week) times x (The amount of weeks) plus 25(the amount he already has) equals y(the amount of everything put together)

5 0
3 years ago
the angle theta is located in quadrant 1 and cos of theta is 3/8. what is the value of sin of theta ?
ra1l [238]

Answer: sin of theta = (√55)/8

Step-by-step explanation:

Cosine is the x-value divided by the hypotenuse. We now know that since cosine is 3/8, that the hypotenuse is 8. In order to find the third side of the triangle (which would be the v-value), we must use Pythagorean theorem. The third side is square root 55. Sine equals the y-value divides by the hypotenuse. We know both of those values, so Sine of theta = square root of 55 divided by 8.

8 0
3 years ago
Jonathon has a bag that contains exactly one red marble (r), one yellow marble (y), and one green marble (g). He chooses a marbl
wariber [46]

Answer:

          [ry, yr, gy, yg, rg, gr]-Any three picks from this sample space.

Step-by-step explanation:

-The bag contains exactly 1r, \ 1y, \ 1g \ marbles.

-He picks one ball without looking, and chooses a second ball without replacing the first:

  • If the first is red, the the second is either yellow or green,
  • If the first is a yellow, then the second can be red or green,
  • If the first is green, then the second can be a red or yellow.

The sample space of the second pick is therefore:

                               [ry, yr, gy, yg, rg, gr]

Hence, any three picks from the sample space are correct possible outcomes.

7 0
3 years ago
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