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denis23 [38]
3 years ago
6

In a bag of solid colored marbles,1/3 of the marbles are red, 1/4 are green,1/6 are blue, and the rest are yellow. There are 8 m

arbles in the bag. How many in the bag are yellow?
Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

Step-by-step explanation:

so there are 8 marbles in the bag....1/3 red, 1/4 green, 1/6 blue....rest are yellow

red ones.....1/3(8) = 8/3 = 2 2/3 are red

green ones....1/4(8) = 8/4 = 2 are green

blue ones......1/6(8) = 8/6 = 1 1/3 are blue

2 2/3 + 2 + 1 1/3 = 6 marbles are not yellow.......that leaves you with 2 yellow marbles

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The expression is 3 (x+4)-(2x+7) what is that equivalent too
posledela

Answer:

x+19

Step-by-step explanation:

3x+12 - 2x+7 = x+19

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3 years ago
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Ken wants to buy some coffee mugs, m , that cost $5 each and some ground coffee, C, that costs $8 a pound. He has $25.
ValentinkaMS [17]

The inequality representation of the scenario is :

  • 5m + 8c ≤ 25
  • m = 1 and c = 1

  • Number of mugs = m
  • Cost per mug = $5
  • Number of ground coffee = c
  • Cost per ground coffee = $8
  • Total amount to spend = $25

  • (Number of mug × cost per mug) + (Number of ground coffee × cost of ground coffee) ≤total amount to spend

  • Representing as an inequality : 5m + 8c ≤ 25

Combination of m and c that makes the inequality true :

  • Using trial by error :
  • m = 1 and c = 1
  • 5(1) + 8(1) ≤ 25 ; 13 ≤ 25

Hence, m = 1 and c =1 are valid values for the expression.

Learn more : brainly.com/question/15748955

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2 years ago
Please Help I will reward Brainliest answer in centimeters
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8.4 inches

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3 years ago
The price of a shirt is marked down from $12.50 to $10,00. What is the percent decrease of the shirt?
choli [55]

Answer: 20%.

Step-by-step explanation:

Given, The price of a shirt is marked down from $12.50 to $10.00.

Previous price = $12.50

New price = $10.00

Change in price = Previous price - New price

= $12.50 - $10.00

= $2.50

Now, the percent decrease of the shirt = \dfrac{\text{Change in price}}{\text{Prevoius price}}\times100

=\dfrac{2.50}{12.50}\times100\\\\=20\%

Hence, the percent decrease of the shirt = 20%.

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Strain-displacement relationship) Consider a unit cube of a solid occupying the region 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1 After loa
Anastasy [175]

Answer:

please see answers are as in the explanation.

Step-by-step explanation:

As from the data of complete question,

0\leq x\leq 1\\0\leq y\leq 1\\0\leq z\leq 1\\u= \alpha x\\v=\beta y\\w=0

The question also has 3 parts given as

<em>Part a: Sketch the deformed shape for α=0.03, β=-0.01 .</em>

Solution

As w is 0 so the deflection is only in the x and y plane and thus can be sketched in xy plane.

the new points are calculated as follows

Point A(x=0,y=0)

Point A'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point A'(0+<em>(0.03)</em><em>(0),0+</em><em>(-0.01)</em><em>(0))</em>

Point A'(0<em>,0)</em>

Point B(x=1,y=0)

Point B'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point B'(1+<em>(0.03)</em><em>(1),0+</em><em>(-0.01)</em><em>(0))</em>

Point <em>B</em>'(1.03<em>,0)</em>

Point C(x=1,y=1)

Point C'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point C'(1+<em>(0.03)</em><em>(1),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>C</em>'(1.03<em>,0.99)</em>

Point D(x=0,y=1)

Point D'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point D'(0+<em>(0.03)</em><em>(0),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>D</em>'(0<em>,0.99)</em>

So the new points are A'(0,0), B'(1.03,0), C'(1.03,0.99) and D'(0,0.99)

The plot is attached with the solution.

<em>Part b: Calculate the six strain components.</em>

Solution

Normal Strain Components

                             \epsilon_{xx}=\frac{\partial u}{\partial x}=\frac{\partial (\alpha x)}{\partial x}=\alpha =0.03\\\epsilon_{yy}=\frac{\partial v}{\partial y}=\frac{\partial ( \beta y)}{\partial y}=\beta =-0.01\\\epsilon_{zz}=\frac{\partial w}{\partial z}=\frac{\partial (0)}{\partial z}=0\\

Shear Strain Components

                             \gamma_{xy}=\gamma_{yx}=\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}=0\\\gamma_{xz}=\gamma_{zx}=\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}=0\\\gamma_{yz}=\gamma_{zy}=\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}=0

Part c: <em>Find the volume change</em>

<em></em>\Delta V=(1.03 \times 0.99 \times 1)-(1 \times 1 \times 1)\\\Delta V=(1.0197)-(1)\\\Delta V=0.0197\\<em></em>

<em>Also the change in volume is 0.0197</em>

For the unit cube, the change in terms of strains is given as

             \Delta V={V_0}[(1+\epsilon_{xx})]\times[(1+\epsilon_{yy})]\times [(1+\epsilon_{zz})]-[1 \times 1 \times 1]\\\Delta V={V_0}[1+\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}+\epsilon_{xx}\epsilon_{zz}+\epsilon_{yy}\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}\epsilon_{zz}-1]\\\Delta V={V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the strain values are small second and higher order values are ignored so

                                      \Delta V\approx {V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\ \Delta V\approx [\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the initial volume of cube is unitary so this result can be proved.

5 0
3 years ago
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