Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
Its the first choice: right, scalene.
Step-by-step explanation:
It is a right angled triangle, (indicated by the little square at Q).
The sides have different lengths so it scalene.
Answer:
The one on the right is 25 percent smaller then the one on the left. They have he same angle measures. The line lengths are just different.
Step-by-step explanation:
Hope this helps.
Answer:
(a) (6, 2)
Step-by-step explanation:
The system of equations has one of them in y= form, so it lends itself to solution by substitution.
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Using the equation for y to substitute into the first equation, we have ...
2x -y = 10
2x -(-1/2x +5) = 10 . . . . . substitute for y
2x +1/2x -5 = 10 . . . . . eliminate parentheses
5/2x = 15 . . . . . . . . . add 5, collect terms
x = 6 . . . . . . . . . . . multiply by 2/5
Using the equation for y, we have ...
y = -1/2(6) +5 = -3 +5
y = 2
The solution is (x, y) = (6, 2).
STEP-BY-STEP SOLUTION:
= x^2 - 13x + 30
= x^2 - 10x - 3x + 30
= x ( x - 10 ) - 3 ( x - 10 )
= ( x - 10 ) ( x - 3 )
FINAL ANSWER:
Therefore, the answer is:
C. x - 10
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Thank you and have a lovely day! <3
