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3 years ago

The probability distribution of all possible values of the sample proportion is the

1 answer:

4 0

Answer: The sampling distribution of p is the probability distribution of all possible values of the sample proportion p.

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Help i will be giving brainliest!!

Elena L [17]

See the photo attached below, answer is D

4 0

3 years ago

How do I do this? Find the distance between the points given. Simplify all irrational answers.

belka [17]

The formula for finding the distance between points is √(x-x₁)²+(y-y₁)²
x=0, y=6, x₁=5, y₁=12
√(0-5)²+(6-12)²
√(-5)²+(-6)²
√25+36
√61 is irrational
7.81 points(rounded to nearest hundredth) is the distance between those two points.

8 0

4 years ago

An object is thrown from a height of 5 in. After 2 s, the object reaches a maximum height of 9 in, and then it lands back on the

Marta_Voda [28]

Answer:

y=-(x-2)^2+9

Step-by-step explanation:

Hope this helps

7 0

3 years ago

Solve the given inequality :

tigry1 [53]

Answer:

x < -5 or x = 1 or 2 < x < 3 or x > 3

Step-by-step explanation:

Given rational inequality:

$\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0$

$\textsf{Factor }(x^2-5x+6):$

$\implies x^2-2x-3x+6$

$\implies x(x-2)-3(x-2)$

$\implies (x-3)(x-2)$

Therefore:

$\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0$

Find the roots by solving f(x) = 0 (set the numerator to zero):

$\implies (x-1)^2(x-2)^3=0$

$\implies (x-1)^2=0\implies x=1$

$\implies (x-2)^3=0 \implies x=2$

Find the restrictions by solving f(x) = undefined (set the denominator to zero):

$\implies (x-3)^2(x-2)^2(x+5)=0$

$\implies (x-3)^2=0 \implies x=3$

$\implies (x-2)^2=0 \implies x=2$

$\implies (x+5)=0 \implies x=-5$

Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values: -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

$f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+$

$f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

$f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5 or x = 1 or 2 < x < 3 or x > 3

As interval notation:

$(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)$

4 0

2 years ago

What is the equation of the line

olga2289 [7]

Answer:

It's the first choice y = (-5/2)x - 1.

Step-by-step explanation:

First find the slope of the line 5x + 2y = 12 by converting to slope-intercept form.

5x + 2y = 12

2y = -5x + 12

y = (-5/2)x + 6 so the slope is (-5/2).

The line we require had also a slope of -5/2 because it is parallel to the first line and it also passes through the point (-2, 4). So:

y - 4 = (-5/2)(x - -2) (the point-slope form)

y - 4 = (-5/2)(x + 2)

y = (-5/2)x - 5 + 4

y = (-5/2)x - 1 (answer)

7 0

3 years ago