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3 years ago

Help please is for Algebra

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Answer:

$=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}$

the third option is your answer

Step-by-step explanation:

$\frac{5}{a-3}+\frac{3}{a+3}\\\mathrm{Least\:Common\:Multiplier\:of\:}a-3,\:a+3:\quad \left(a-3\right)\left(a+3\right)\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\=\frac{5\left(a+3\right)}{\left(a-3\right)\left(a+3\right)}+\frac{3\left(a-3\right)}{\left(a+3\right)\left(a-3\right)}\\\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{5\left(a+3\right)+3\left(a-3\right)}{\left(a-3\right)\left(a+3\right)}$

$\mathrm{Expand}\:5\left(a+3\right)+3\left(a-3\right):\quad 8a+6\\=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}$

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Also, number less than 4, is equal to ={1,2,3}, but in the statement, it is given that,number less than 4, it’s sample space is A={1,2,3,4},which is Incorrect.

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Answer:

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Step-by-step explanation:

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Therefore, in this case , for

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