All categories

3 years ago

Help please is for Algebra

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Answer:

$=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}$

the third option is your answer

Step-by-step explanation:

$\frac{5}{a-3}+\frac{3}{a+3}\\\mathrm{Least\:Common\:Multiplier\:of\:}a-3,\:a+3:\quad \left(a-3\right)\left(a+3\right)\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\=\frac{5\left(a+3\right)}{\left(a-3\right)\left(a+3\right)}+\frac{3\left(a-3\right)}{\left(a+3\right)\left(a-3\right)}\\\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{5\left(a+3\right)+3\left(a-3\right)}{\left(a-3\right)\left(a+3\right)}$

$\mathrm{Expand}\:5\left(a+3\right)+3\left(a-3\right):\quad 8a+6\\=\frac{8a+6}{\left(a-3\right)\left(a+3\right)}$

You might be interested in

By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00pm positive or negative?

Ad libitum [116K]

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

6 0

3 years ago

John has a box that is in the shape of a cube (i.

Artemon [7]

A box (cube) has all equal edges or sides (s), thus the volume (v) of the cube is:
$v = {s}^{3} \\ 27 \: {in}^{3} = {s}^{3} \\ \sqrt{( {s}^{3}) } = \sqrt{( {27in}^3)} \\ s = 3 \: in$
So since each side or edge around is 3 in, then the length around the square bottom of the box = 4×3 = 12 in

5 0

3 years ago

Micheal is 5 years older than Rui Feng and Vishal is thrice as old as Micheal if Rui Feng is p years old, find i) Michael's pres

Kitty [74]

Answer:

Michael's present age = p + 5

Michael's present age = 3p + 15

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = 5p - 11

Step-by-step explanation:

Assume;

Age of Rui Feng = x

Age of Micheal = x + 5

Age if Vishal = 3[x+5]

Given:

Age of Rui Feng = P

Computation:

Michael's present age = Age of Rui Feng + 5

Michael's present age = p + 5

Vishal's present age = 3[p + 5]

Michael's present age = 3p + 15

Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3

Sum of there ages 3 year ago = 5p - 11

8 0

2 years ago

What is the value of z?

OLga [1]

Answer:

z = 86

Explanation:

90 - 68 = 12
180 - 78 = 102
102 + 12 = 114
180 - 114 = 86

3 0

3 years ago

Read 2 more answers

Answer!! Please. Will give brain.

damaskus [11]

Answer:

Step-by-step explanation:

Just trust me on this. It has got to be 58.

7 0

10 months ago