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AURORKA [14]
4 years ago
10

Cation Name Cation Symbol

Chemistry
1 answer:
Crazy boy [7]4 years ago
6 0
Usual s I have no idea sorry
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Is this line real or imaginary?
irga5000 [103]

Answer:

imaginary because i see no line.

Explanation:

8 0
3 years ago
A given reaction has an activation energy of 24.52 kj/mol. at 25°c, the half-life is 4 minutes. at what temperature will the hal
igor_vitrenko [27]
According to half life equation:

T(1/2) = ㏑2 / K1

when the T(1/2) = 4 min * 60 = 240 sec

by substitution:

240 = 0.6931 / K1

K1 = 2.9 x 10^-3

when the second T(1/2) = 20 sec, so to get K2:

T(1/2) = 0.6931 / K2

by substitution:

20 = 0.6931 / K2

∴K2 = 3.4 x 10^-2

so, we can get T2 by using this formula:

㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)

by substitution:

㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)

∴ T2 = 396.7 K

         = 396.7 - 273 = 123.7 °C 



4 0
3 years ago
An unknown compound contains only C , H , and O . Combustion of 5.60 g of this compound produced 13.7 g CO2 and 5.60 g H2O . Wha
son4ous [18]

Answer:

Empirical formula of compound  is C₄H₈O

Explanation:

Given data:

Mass of compound = 5.60 g

Mass of CO₂ = 13.7 g

Mass of H₂O = 5.60 g

Empirical formula of compound = ?

Solution:

Percentage of C:

13.7 g/5.60 g × 12/44× 100

2.45×0.273× 100 = 66.9%

Percentage of H:

5.60 g/ 5.60 g × 2.016/18 × 100

11.2%

Percentage of O:

(66.9% + 11.2%) - 100 = 21.9%

Grams atom of  C , H, O

66.9/12 = 5.6

11.2 / 1.008 = 11.11

21.9 / 16 = 1.4

Atomic ratio:

           C                 :               H           :              O

           5.6/1.4         :            11.11/1.4    :            1.4/1.4

              4                :               8            :               1

Empirical formula:

C₄H₈O

7 0
4 years ago
Which of the following will have the slowest rate of diffusion at a given temperature?
marysya [2.9K]
<h3>Answer:</h3>

Chlorine gas (Cl₂)

<h3>Explanation:</h3>
  • According to the Graham's law of diffusion, the diffusion rate of a gas is inversely proportional to the square root of its density or molar mass.
  • Therefore, a lighter gas will diffuse faster at a given temperature compared to a heavy gas.
  • Consequently, the heavier a gas is then the denser it is and the slower it diffuses at a given temperature and vice versa.

In this case we are given gases, CI₂

, H₂,He and Ne.

  • We are required to identify the gas that will diffuse at the slowest rate.
  • In other words we are required to determine the heaviest gas.

Looking at the molar mass of the gases given;

Cl₂- 70.91 g/mol

H₂- 2.02 g/mol

He - 4.00 g/mol

Ne- 20.18 g/mol

Therefore, chlorine gas is the heaviest and thus will diffuse at the slowest rate among the choices given.

8 0
3 years ago
What describes how computer programs convert design sketches into three dimensional images
weeeeeb [17]

Answer:

The programs take two-dimensional images and allow the user to manipulate cubes and prisms to create their design sketches.

Explanation:

Instead of working with squares and triangles, the programs allow the users to manipulate cubes and prisms to create their design sketches. Additionally, the programs can take two-dimensional pictures and convert them to possible three-dimensional images.

I got you bro :)

Sorry he took your points :(

- massmaster34

4 0
3 years ago
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