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tigry1 [53]
3 years ago
10

The molar mass of NaOH is 40.00 g/mol. If 5.20 g NaOH are dissolved in 0.500 L of solution, what is the molarity of the solution

?
Chemistry
2 answers:
seropon [69]3 years ago
6 0
Answer is 0.26

Molarity of the solution is 

<span>[ 5.20g / 0.5L ] x [1mole / 40.00g] =0.26</span>
Sav [38]3 years ago
6 0

Answer: The molarity of the solution is 0.26M

Explanation: Molarity of the solution is defined as the number of moles of solute present in a liter volume of solution.

Mathematically,

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Number of moles is expressed by using the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Putting this in above equation, we get:

Molarity=\frac{\text{Given mass of solute (in grams)}}{\text{Molar mass of solute}\times\text{volume of solution (in L)}}

Given mass of solute (NaOH) = 5.20 g

Molar mass of solute (NaOH) = 40 g/mol

Volume of solution = 0.500 L

Putting values in above equation, we get:

Molarity=\frac{5.20g}{40g/mol\times 0.5L}=0.26mol/L

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