Answer:
Function 2 is changing more rapidly
Step-by-step explanation:
We need to find the slope of each function to determine which one is changing more rapidly
m = (y2-y1)/(x2-x1)
Function1
(0,20) and (5,0)
m = (0-20)/(5-0)
= -20/5
= -4
Function 2
(2,11) and (4,2)
m = (2-11)/(4-2)
= -9/2
= -4.5
We do not care about the sign, just the number when we determine which one is changing more rapidly. The sign tells the direction, the number tells the rate.
|-4| < |-4.5|
4 < 4.5
Function 2 is changing more rapidly
Answer:
0.075 is less
Step-by-step explanation:
It is 0.075 because 0.96 is closer to 1 and so is greater
B is in standard form
Step-by-step explanation: standard form is y=mx+b
Answer:
Step-by-step explanation i dont know
Given :
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level.
When the lake warms up in the summer, the trout swim 20 feet deeper than that , d = 20 feet .
To Find :
At what position relative to sea level do the trout swim in the summer.
Solution :
Depth in spring from surface ,
.
Let , depth in summer is D .
Now , depth in summer relative to sea-level is :
![D=D_s+d\\\\D=30+20\ feet\\\\D=50\ feet](https://tex.z-dn.net/?f=D%3DD_s%2Bd%5C%5C%5C%5CD%3D30%2B20%5C%20feet%5C%5C%5C%5CD%3D50%5C%20feet)
Therefore , trout swim 50 feet deep below the sea level in the summer .
Hence , this is the required solution .