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Cerrena [4.2K]
3 years ago
15

Are these answers right or some wrong? If some wrong plz answer them correct thanks!

Mathematics
2 answers:
maxonik [38]3 years ago
7 0

You are wrong.

1, 2, 3 and 4 are correct.

5. 75%

6 is also correct

7. 100%

8. 50%

Korvikt [17]3 years ago
6 0
No they aren’t, you got most right:)
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c) 1/3

Step-by-step explanation:

since there are 6 sides to the dice and 2 options could be chosen= 2/6 and that simplified is 1/3

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The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of the games did they win?
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They won 6/11 games.

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3 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
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