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earnstyle [38]
4 years ago
8

If (z°z)(x)=1/16x , what is z (x)?

Mathematics
1 answer:
vivado [14]4 years ago
6 0
<span>assume z = ax for simplicity z(z) = a(ax) = a^2x let a^2x = 1/16x and solve for a </span>
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A village loses 20% of their goats to the flood and 5% die from diseases. There are 8084 goats left, how many goats were their o
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10779

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2 years ago
70 × 6000 associative properties
Hatshy [7]
You can do
70 x 6000
and
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8 0
3 years ago
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Solve 2x2 8x - 12 = 0 by completing the square. show step-by-step solution
malfutka [58]
Group x terms
(2x^2+8x)-12=0
undistribute 2
2(x^2+4x)-12=0
take 1/2 of 4 and square it, add negative and positive of it insde (2^2=4)
2(x^2+4x+4-4)-12=0
factor perfect square
2((x+2)^2-4)-12=0
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2(x+2)^2-20=0
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8 0
3 years ago
Help Please!!!! 22pts!!!!!
laila [671]

Answer:

1.) 7/20 or StartFraction 7 Over 20 EndFraction

please put this as brainliest

Step-by-step explanation:

3 investors:

1 investor= 1/4 or 5/20

2 investor= 2/5 or 8/20

1+2 investors= 13/20

3rd investor = 7/20

3 0
3 years ago
Read 2 more answers
The recursive function LaTeX: f\left(0\right)=1,\:f\left(n\right)=f\left(n-1\right)+2nf ( 0 ) = 1 , f ( n ) = f ( n − 1 ) + 2 n
m_a_m_a [10]

Question:

The recursive function f(0) = 1, f(n) = f(n-1) + 2n represents the nth term of a sequence. Determine the explicit function

Answer:

f(n) = n^2 + n+1

Step-by-step explanation:

Given

f(0) = 1

f(n) = f(n-1) + 2n

Required

Write an explicit formula

Let n = 1

f(1) = f(1-1) + 2*1

f(1) = f(0) + 2

f(1) = 1 + 2 = 3

Let n = 2

f(2) = f(2-1) + 2*2

f(2) = f(1) + 4

f(2) = 3 + 4 = 7

Let n =3

f(3)=f(3-1) + 2 * 3

f(3)=f(2) + 6

f(3)=7+ 6 = 13

Let n = 4

f(4) = f(4 - 1) + 2 * 4

f(4) = f(3) + 8

f(4) = 13+ 8 = 21

So, we have:

f(1) = 3= 1 + 2 * 1=1+0*1*2*1

f(2) = 7= 3 + 2 * 2=1+1*2+2*2  

f(3) = 13= 7 + 2 * 3= 1+2*3+2*3

f(4) = 21 = 13 + 2 * 4= 1+3*4 +2 *4

Following the above pattern:

f(n) = 1 + (n - 1) * n + 2 * n

f(n) = 1 + n(n - 1) + 2n

Open bracket

f(n) = 1 + n^2 - n + 2n

f(n) = 1 + n^2 + n

f(n) = n^2 + n+1

3 0
3 years ago
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