Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
Answer: 3 ft. and 2 inches
38÷12=3.2
12×3=36
38-36
Change the fraction into a decimal
153.86 is the answer because the formula is Pi times radius squared. So, the equation would be 3.14X7^2=3.14X49=153.86
Answer:
My answer was deleted but it was between 4 and 6 weeks
Step-by-step explanation:
